Question

Darin is 4 feet 10 inches tall. His brother is 68 inches tall. How many feet inches is Darin's brother than Darin?

Answer 1

Hint: Let us find the relation between inches and feet. 1 foot is equal to 12 inches. Based on this relation, we can find the height of the Darin in inches. For that, we will multiply the height by 12 inches. Then we will subtract the height of both brothers to find the difference.

Complete step-by-step answer:
Here, the first step is to convert the height of Darin from feet and inches into inches.
As we already know that 1 foot = 12 inches.
Therefore, to convert 4 feet into inches, multiply 4 by 12.
$ \Rightarrow 4 \times 12$
Let us multiply the above step.
The answer will be,
$ \Rightarrow 48$
Hence, the total height of Darin is 48+10 inches.
That is equal to 58 inches.
Darin’s brother's height is already given here.
Therefore, the difference between the heights of both brothers are
$ \Rightarrow 68 - 58$
The answer is 10 inches.

Hence, Darin’s brother is 10 inches taller than Darin.

Note:
The use of a unit depends on the situation, such as the area of a room is expressed in meters but the length of a pencil is expressed in centimetres and its thickness in millimetres. Thus, we need to convert one unit to another. Points to remember while converting units:
> To convert a bigger unit to a smaller unit, we have to apply multiplication.
> To convert a smaller unit to a bigger unit, we have to apply division.