Question

Darin is 4 feet 10 inches tall. His brother is 68 inches tall. How many feet inches taller is Darin’s brother than Darin?
 (a) 1 feet
(b) 10 inches
(c) 11 inches
(d) 2 inches

Answer 1

Hint: We have the problem as Darin has a height of 4 feet 10 inches and his brother is 68 inches tall. We are to initially find the height of Darin in a proper unit in inches or feet. So that we can find the difference of height getting the difference of the numbers.

Complete step by step solution:
According to the question, Darin is 4 feet 10 inches tall.
Now, we all know, 1 feet is equal to 12 inches.
So, 4 feet is equal to $\left( 4\times 12 \right)$ inches.
Simplifying we get, 48 inches.
Thus, we get 4 feet 10 inches equal to (48 +10) = 58 inches.
Again, according to the question, his brother is 68 inches.
So, the difference in height is, ( 68 -58 ) inches.
Thus the height difference between Darin and his brother is 10 inches.
So, Darin’s brother is 10 inches taller than Darin.
Hence the solution is, (b) 10 inches.

Note: We can solve this problem by changing the units into feet also. So, 68 inches will turn out to be 5 feet and 8 inches. So, the difference of height in Darin and Darin’s brother would be, ( 5 feet 8 inches – 4 feet 10 inches) = 10 inches. Hence, we always get the right answer in any way possible.