$C{u_2}S$ and ${M_2}S$ are isomorphous in which percentage of Sulphur is 20.14%. and 12.94% respectively. The atomic weight of M is:
A. 208
B. 108
C. 112
D. 106
Answer
611.4k+ views
Hint: To calculate the atomic weight of M, first we need to find the mass of Sulphur. The formula used for the calculation is mass percentage. Mass percentage is calculated by dividing the mass of compound x with total mass of compound x and y multiplied by 100.
Complete step by step answer:
The percentage of Sulphur in $C{u_2}S$is 20.14 %
The percentage of Sulphur in ${M_2}S$is 12.94%
The atomic weight of Cu is 63.5.
The mass percentage is calculated by mass of compound x divided by total mass of compound x and compound y multiplied with 100.
The formula for calculating the mass percentage is shown below.
$mass\% = \dfrac{{mass\,of\;x}}{{mass\;of\;x + mass\;of\;y}} \times 100$
Where,
x is the mass of compound x.
y is the mass of compound y.
Let assume that the x be the mass of Sulphur.
In $C{u_2}S$, from two mole of Cu one mole of Sulphur is present. Therefore the mass of copper will be 127.
To calculate the mass of Sulphur substitute, the values in the equation.
$ \Rightarrow 20.14\% = \dfrac{{mass\,of\;x}}{{mass\;of\;x + 127}} \times 100$
$ \Rightarrow 100x = 2557.78 + 20.14x$
$ \Rightarrow x = \dfrac{{2557.78}}{{79.86}}$
$ \Rightarrow x = 32$
Let assume that the atomic weight of silver is W.
In ${M_2}S$, for two mole of M one mole of Sulphur is present.
To calculate the atomic weight of M, substitute the values in the equation.
$ \Rightarrow 12.94\% = \dfrac{{32}}{{32 + 2W}} \times 100$
$ \Rightarrow 12.94\% = \dfrac{{1600}}{{16 + W}}$
$\Rightarrow$ 1600= 12.94W + 12.94 $\times$ 16
$\Rightarrow$ 12.94W = 1600 - 12.94 $\times$ 16
$ \Rightarrow 12.94W = 1392.96$
$ \Rightarrow W = \dfrac{{1392.96}}{{12.94}}$
$ \Rightarrow W = 108g$
Thus, the atomic weight of M is 108g.
So, the correct answer is “Option B”.
Note:
Make sure that in the given compounds for every 2 mole of metal, 1 mole of Sulphur is present, it will help in determining the mass of metal with the help of its atomic weight.
Complete step by step answer:
The percentage of Sulphur in $C{u_2}S$is 20.14 %
The percentage of Sulphur in ${M_2}S$is 12.94%
The atomic weight of Cu is 63.5.
The mass percentage is calculated by mass of compound x divided by total mass of compound x and compound y multiplied with 100.
The formula for calculating the mass percentage is shown below.
$mass\% = \dfrac{{mass\,of\;x}}{{mass\;of\;x + mass\;of\;y}} \times 100$
Where,
x is the mass of compound x.
y is the mass of compound y.
Let assume that the x be the mass of Sulphur.
In $C{u_2}S$, from two mole of Cu one mole of Sulphur is present. Therefore the mass of copper will be 127.
To calculate the mass of Sulphur substitute, the values in the equation.
$ \Rightarrow 20.14\% = \dfrac{{mass\,of\;x}}{{mass\;of\;x + 127}} \times 100$
$ \Rightarrow 100x = 2557.78 + 20.14x$
$ \Rightarrow x = \dfrac{{2557.78}}{{79.86}}$
$ \Rightarrow x = 32$
Let assume that the atomic weight of silver is W.
In ${M_2}S$, for two mole of M one mole of Sulphur is present.
To calculate the atomic weight of M, substitute the values in the equation.
$ \Rightarrow 12.94\% = \dfrac{{32}}{{32 + 2W}} \times 100$
$ \Rightarrow 12.94\% = \dfrac{{1600}}{{16 + W}}$
$\Rightarrow$ 1600= 12.94W + 12.94 $\times$ 16
$\Rightarrow$ 12.94W = 1600 - 12.94 $\times$ 16
$ \Rightarrow 12.94W = 1392.96$
$ \Rightarrow W = \dfrac{{1392.96}}{{12.94}}$
$ \Rightarrow W = 108g$
Thus, the atomic weight of M is 108g.
So, the correct answer is “Option B”.
Note:
Make sure that in the given compounds for every 2 mole of metal, 1 mole of Sulphur is present, it will help in determining the mass of metal with the help of its atomic weight.
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