QUESTION

# Corresponding sides of two similar triangles are in the ratio 2:3. If the area of the Smaller triangle is $48c{m^2}$ , to determine the area of the larger triangle.

$\dfrac{{{\text{area of smaller triangle}}}}{{{\text{area of larger triangle}}}} = {\left( {\dfrac{2}{3}} \right)^2} \\ \\$
$\dfrac{{48}}{{{\text{area of larger triangle}}}} = \dfrac{4}{9} \\ \therefore {\text{area of larger triangle = }}\dfrac{{48 \times 9}}{4} = 108c{m^2} \\$
Hence the area of the larger triangle is $108c{m^2}$ .