Answer
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Hint
a) In the formula of force from the second law of motion, $F = ma$ , when ‘m’ and ‘a’ are in SI units then the unit of force is found to be Newton.
b) You can refer to Newton’s third law of motion for the correct statement.
Complete step-by-step solution:Let us first discuss about statement (a)
From Newton’s second law we know that $F = ma$ where $F$ is the force in Newton, $m$ is the mass in kg and $a$ is the acceleration in $m{s^{ - 2}}$ .
So, we can say that $1N = 1kg \times 1m{s^{ - 2}}$
Therefore we can define the standard metric unit of force using the above equation. So, 1 Newton is the amount of force that is required to give a 1-kg mass an acceleration of $1m{s^{ - 2}}$ .
So, the correct statement is “1 newton is the force that produces an acceleration of \[1m{s^{ - 2}}\] in an object of 1 kg mass.”
Now, let us discuss about statement (b)
Newton's third law of motion explains the relation between action and reaction. It states that for every action there is an equal and opposite reaction which acts on two different bodies. For example, if a ball of mass m is at rest on a table. The action force 'mg' is applied by ball on the table while the reaction force 'N' is applied by the table on the ball in the form of Normal reaction (which has magnitude equal to 'mg'), hence they do not cancel.
So, the correct statement is “Action and reaction are always acting on two different bodies.”
Note: We can explain the behavior of objects for which all existing forces are not balanced using Newton's second law of motion. It states that the acceleration of an object depends upon two variables which are the net force acting upon the object and the mass of the object. The acceleration of any particle or object is inversely proportional to its mass and directly proportional to the net force acting upon it.
a) In the formula of force from the second law of motion, $F = ma$ , when ‘m’ and ‘a’ are in SI units then the unit of force is found to be Newton.
b) You can refer to Newton’s third law of motion for the correct statement.
Complete step-by-step solution:Let us first discuss about statement (a)
From Newton’s second law we know that $F = ma$ where $F$ is the force in Newton, $m$ is the mass in kg and $a$ is the acceleration in $m{s^{ - 2}}$ .
So, we can say that $1N = 1kg \times 1m{s^{ - 2}}$
Therefore we can define the standard metric unit of force using the above equation. So, 1 Newton is the amount of force that is required to give a 1-kg mass an acceleration of $1m{s^{ - 2}}$ .
So, the correct statement is “1 newton is the force that produces an acceleration of \[1m{s^{ - 2}}\] in an object of 1 kg mass.”
Now, let us discuss about statement (b)
Newton's third law of motion explains the relation between action and reaction. It states that for every action there is an equal and opposite reaction which acts on two different bodies. For example, if a ball of mass m is at rest on a table. The action force 'mg' is applied by ball on the table while the reaction force 'N' is applied by the table on the ball in the form of Normal reaction (which has magnitude equal to 'mg'), hence they do not cancel.
So, the correct statement is “Action and reaction are always acting on two different bodies.”
Note: We can explain the behavior of objects for which all existing forces are not balanced using Newton's second law of motion. It states that the acceleration of an object depends upon two variables which are the net force acting upon the object and the mass of the object. The acceleration of any particle or object is inversely proportional to its mass and directly proportional to the net force acting upon it.
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