Question

Correct set of four quantum numbers for the valence (outermost) electron of rubidium (Z=37) :
(A) $5,0,0, + \dfrac{1}{2}$
(B) $5,1,0, + \dfrac{1}{2}$
(C) $5,1,1, + \dfrac{1}{2}$
(D) $6,0,0, + \dfrac{1}{2}$

Answer 1

Hint: According to the question, first we should write the electronic configuration of Rubidium and then we will write about the given element Rubidium.

Complete step-by-step answer: Given, atomic number of Rb, Z=37. Thus, its electronic configuration is $[Kr]5{s^1}$ . Since, the last electron or valence electron enters in $5s$ subshell. So, the quantum numbers are n=5,l=0;
(for s-orbital) m=0 $(\because m = + l\,to\, - l)$ , s=$ + \dfrac{1}{2}$ or $ - \dfrac{1}{2}$ .
Rubidium is a chemical element with atomic number 37 which means there are 37 protons and 37 electrons in the atomic structure. Rubidium is a very soft, silvery-white metal in the alkali metal group. Rubidium metal shares similarities to potassium metal and caesium metal in physical appearance, softness and conductivity. Rubidium cannot be stored under atmospheric oxygen, as a highly exothermic reaction will ensue, sometimes even resulting in the metal catching fire. Rubidium (Rb), chemical element of Group 1 (Ia) in the periodic table, the alkali metal group. Rubidium is the second most reactive metal and is very soft, with a silvery-white lustre.
Rubidium was found (1861) spectroscopically by German researchers Robert Bunsen and Gustav Kirchhoff and named after the two conspicuous red lines of its range. Rubidium and cesium regularly happen together in nature. Rubidium, be that as it may, is all the more generally dissipated and only from time to time frames a characteristic mineral; it is discovered uniquely as a pollution in different minerals, running in substance up to 5 percent in such minerals as lepidolite, pollucite, and carnallite.

Note: The extraction of rubidium from gold waste from the Mouteh processing plant in Iran by a three-step process (acid washing, followed by salt roasting and water leaching) was optimized.