
When Copper is reacted with concentrated sulphuric acid, which gas is evolved?
A. ${H_2}$
B. \[{O_2}\]
C. \[S{O_2}\]
D. \[S{O_3}\]
Answer
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Hint: In order to answer the question, first we have to write the balanced reaction between copper and concentrated sulphuric acid and then observe the product of which gas is evolving during the reaction.
Complete step-by-step answer:Copper doesn’t react easily, hence dilute ${H_2}S{O_4}$ will have no reaction. But concentrated Sulphuric Acid ${H_2}S{O_4}$ will react and sulphur dioxide \[S{O_2}\] and water are evolved, and copper sulphate is formed. So, the reaction is as follows:
\[Cu + 2{H_2}S{O_4} \to CuS{O_4} + S{O_2} + 2{H_2}O\]
There are numerous associations among copper and sulphuric acid. Copper doesn't disintegrate in numerous acids, however in concentrated sulphuric acid it separates by responding. Consolidating copper and sulphuric acid can deliver hydrates, or copper particles that are stuck to water. Power can be produced when copper interacts with the best possible sulphuric acid arrangement. Copper salts can be made in a reaction of sulphuric corrosive and copper oxide.Blending copper and sulphuric acid makes the copper change properties and oxidize, or respond. This oxidizing makes copper break up into copper intensifies that structure the two hydrates and particles. Copper ions are suspended in the arrangement due to the acidic properties of sulphuric acid, which additionally delivers sulphate particles. Hydrates resemble ions, aside from they use water to shape complex particles with the copper ions. Different ions will stay suspended on the grounds that they balance an electrical charge between the copper and sulphate ions.
Hence the correct option is (C).
Note:Copper does not react with dilute sulphuric acid, liberating hydrogen because copper is lower in electromotive series than hydrogen, or more fundamentally, because the greatness of progress in gibbs free energy when a solitary iota of basic hydrogen ionizes is more prominent than the size of the adjustment in gibbs free energy when a solitary particle of natural copper ionizes.
Complete step-by-step answer:Copper doesn’t react easily, hence dilute ${H_2}S{O_4}$ will have no reaction. But concentrated Sulphuric Acid ${H_2}S{O_4}$ will react and sulphur dioxide \[S{O_2}\] and water are evolved, and copper sulphate is formed. So, the reaction is as follows:
\[Cu + 2{H_2}S{O_4} \to CuS{O_4} + S{O_2} + 2{H_2}O\]
There are numerous associations among copper and sulphuric acid. Copper doesn't disintegrate in numerous acids, however in concentrated sulphuric acid it separates by responding. Consolidating copper and sulphuric acid can deliver hydrates, or copper particles that are stuck to water. Power can be produced when copper interacts with the best possible sulphuric acid arrangement. Copper salts can be made in a reaction of sulphuric corrosive and copper oxide.Blending copper and sulphuric acid makes the copper change properties and oxidize, or respond. This oxidizing makes copper break up into copper intensifies that structure the two hydrates and particles. Copper ions are suspended in the arrangement due to the acidic properties of sulphuric acid, which additionally delivers sulphate particles. Hydrates resemble ions, aside from they use water to shape complex particles with the copper ions. Different ions will stay suspended on the grounds that they balance an electrical charge between the copper and sulphate ions.
Hence the correct option is (C).
Note:Copper does not react with dilute sulphuric acid, liberating hydrogen because copper is lower in electromotive series than hydrogen, or more fundamentally, because the greatness of progress in gibbs free energy when a solitary iota of basic hydrogen ionizes is more prominent than the size of the adjustment in gibbs free energy when a solitary particle of natural copper ionizes.
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