
How do you convert $r = 4\sin (2\theta )$ to rectangular form?
Answer
544.5k+ views
Hint: In this question we will use the cartesian format structure and expand the value of $\sin 2\theta $ and use the properties of cartesian form to get the required solution.
Complete step-by-step solution:
We know that the cartesian form of the equation can be expressed in the format:
$r(\cos \theta ,\sin \theta ) = (x,y)$
And we know that: $r = \sqrt {{x^2} + {y^2}} $ .
We also know that $\cos \theta = \dfrac{x}{r}$ and $\sin \theta = \dfrac{y}{r}$
We have the given equation as:
$r = 4\sin (2\theta )$
We know that $\sin 2\theta = 2\sin \theta \cos \theta $ therefore, on expanding the expression, we get:
$\Rightarrow$$r = 4(2\sin \theta \cos \theta )$
On opening the bracket, we get:
$\Rightarrow$$r = 8\sin \theta \cos \theta $
Now we substitute $\sin \theta = \dfrac{y}{r}$ and $\cos \theta = \dfrac{x}{r}$ , on substituting, we get:
$\Rightarrow$$r = 8 \times \dfrac{x}{r} \times \dfrac{y}{r}$
On multiplying the terms, we get:
$\Rightarrow$$r = \dfrac{{8xy}}{{{r^2}}}$
now we know that $r = \sqrt {{x^2} + {y^2}} $ therefore, \[{r^2} = {x^2} + {y^2}\]
on substituting the appropriate values in the equation, we get:
$\Rightarrow$$\sqrt {{x^2} + {y^2}} = \dfrac{{8xy}}{{{x^2} + {y^2}}}$
now on rearranging the equation, we get:
$\Rightarrow$$\sqrt {{x^2} + {y^2}} \times ({x^2} + {y^2}) = 8xy$
Now we know that the root value can be written in the form of exponent as:
$\Rightarrow$${({x^2} + {y^2})^{\dfrac{1}{2}}} \times ({x^2} + {y^2}) = 8xy$
Now using the property of exponents, we can write the term as:
$\Rightarrow$${({x^2} + {y^2})^{\dfrac{3}{2}}} = 8xy$
Now to remove the exponent which is in the form of a fraction, we will square both the sides.
On squaring both the sides, we get:
$\Rightarrow$${({x^2} + {y^2})^3} = {(8xy)^2}$
Now on squaring the terms in the right-hand side, we get:
$\Rightarrow$${({x^2} + {y^2})^3} = 64{x^2}{y^2}$
${({x^2} + {y^2})^3} = 64{x^2}{y^2}$ is the solution for the given question.
Note: It is to be remembered that square root can be written in the form of exponents in the reciprocal form. For example, a term $\sqrt a $ can be written as ${a^{\dfrac{1}{2}}}$ .
The property of exponents is used in the question which is ${a^m}{a^n} = {a^{m + n}}$ .
Another word for the cartesian format is the rectangular format, rectangular or cartesian coordinates are written in the format $(x,y)$ while on the other hand, polar coordinates are written in the form $(r,\theta )$ .
Complete step-by-step solution:
We know that the cartesian form of the equation can be expressed in the format:
$r(\cos \theta ,\sin \theta ) = (x,y)$
And we know that: $r = \sqrt {{x^2} + {y^2}} $ .
We also know that $\cos \theta = \dfrac{x}{r}$ and $\sin \theta = \dfrac{y}{r}$
We have the given equation as:
$r = 4\sin (2\theta )$
We know that $\sin 2\theta = 2\sin \theta \cos \theta $ therefore, on expanding the expression, we get:
$\Rightarrow$$r = 4(2\sin \theta \cos \theta )$
On opening the bracket, we get:
$\Rightarrow$$r = 8\sin \theta \cos \theta $
Now we substitute $\sin \theta = \dfrac{y}{r}$ and $\cos \theta = \dfrac{x}{r}$ , on substituting, we get:
$\Rightarrow$$r = 8 \times \dfrac{x}{r} \times \dfrac{y}{r}$
On multiplying the terms, we get:
$\Rightarrow$$r = \dfrac{{8xy}}{{{r^2}}}$
now we know that $r = \sqrt {{x^2} + {y^2}} $ therefore, \[{r^2} = {x^2} + {y^2}\]
on substituting the appropriate values in the equation, we get:
$\Rightarrow$$\sqrt {{x^2} + {y^2}} = \dfrac{{8xy}}{{{x^2} + {y^2}}}$
now on rearranging the equation, we get:
$\Rightarrow$$\sqrt {{x^2} + {y^2}} \times ({x^2} + {y^2}) = 8xy$
Now we know that the root value can be written in the form of exponent as:
$\Rightarrow$${({x^2} + {y^2})^{\dfrac{1}{2}}} \times ({x^2} + {y^2}) = 8xy$
Now using the property of exponents, we can write the term as:
$\Rightarrow$${({x^2} + {y^2})^{\dfrac{3}{2}}} = 8xy$
Now to remove the exponent which is in the form of a fraction, we will square both the sides.
On squaring both the sides, we get:
$\Rightarrow$${({x^2} + {y^2})^3} = {(8xy)^2}$
Now on squaring the terms in the right-hand side, we get:
$\Rightarrow$${({x^2} + {y^2})^3} = 64{x^2}{y^2}$
${({x^2} + {y^2})^3} = 64{x^2}{y^2}$ is the solution for the given question.
Note: It is to be remembered that square root can be written in the form of exponents in the reciprocal form. For example, a term $\sqrt a $ can be written as ${a^{\dfrac{1}{2}}}$ .
The property of exponents is used in the question which is ${a^m}{a^n} = {a^{m + n}}$ .
Another word for the cartesian format is the rectangular format, rectangular or cartesian coordinates are written in the format $(x,y)$ while on the other hand, polar coordinates are written in the form $(r,\theta )$ .
Recently Updated Pages
Two men on either side of the cliff 90m height observe class 10 maths CBSE

What happens to glucose which enters nephron along class 10 biology CBSE

Cutting of the Chinese melon means A The business and class 10 social science CBSE

Write a dialogue with at least ten utterances between class 10 english CBSE

Show an aquatic food chain using the following organisms class 10 biology CBSE

A circle is inscribed in an equilateral triangle and class 10 maths CBSE

Trending doubts
Why is there a time difference of about 5 hours between class 10 social science CBSE

Write a letter to the principal requesting him to grant class 10 english CBSE

What is the median of the first 10 natural numbers class 10 maths CBSE

The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths

Which of the following does not have a fundamental class 10 physics CBSE

State and prove converse of BPT Basic Proportionality class 10 maths CBSE

