
Convert into factorial: $7\times 8\times 9\times 10\times 11\times 12\times 13\times 14\times 15$.
Answer
500.1k+ views
Hint: We first discuss the concept of factorial. We try to form the given multiplication starting from 1. We multiply the remaining numbers to and also divide them to keep the main expression intact. We convert the multiplication form starting from 1 into their respective factorial form.
Complete step by step answer:
The given multiplication is to be converted to the factorial form. The use for the factorial function is to count how many ways you can choose things from a collection of things.
We know the term $n!$ defines the notion of multiplication of first n natural numbers.
This means $n!=1\times 2\times 3\times ....\times n$.
But the given multiplication $7\times 8\times 9\times 10\times 11\times 12\times 13\times 14\times 15$ does not start from 1.
Therefore, we multiply the terms from 1 to 6 to $7\times 8\times 9\times 10\times 11\times 12\times 13\times 14\times 15$.
We also divide them to balance the number.
So, $7\times 8\times 9\times 10\times 11\times 12\times 13\times 14\times 15=\dfrac{\left( 1\times 2\times ...\times 6 \right)\times \left( 7\times 8\times ......\times 15 \right)}{1\times 2\times ...\times 6}$.
We can see that the numerator is the multiplication of the first 15 natural numbers and the denominator is the multiplication of the first 6 natural numbers.
Therefore, $1\times 2\times ......\times 15=15!$ and $1\times 2\times ......\times 6=6!$.
We get $7\times 8\times 9\times 10\times 11\times 12\times 13\times 14\times 15=\dfrac{15!}{6!}$.
Converting $7\times 8\times 9\times 10\times 11\times 12\times 13\times 14\times 15$ into factorial form we get $\dfrac{15!}{6!}$.
Note: these factorials are mainly used in cases of permutation or combination. In case of combination the simplified form of the mathematical expression ${}^{n}{{C}_{r}}$ is ${}^{n}{{C}_{r}}=\dfrac{n!}{r!\times \left( n-r \right)!}$. In case of permutation the simplified form of the mathematical expression ${}^{n}{{P}_{r}}$ is ${}^{n}{{P}_{r}}=\dfrac{n!}{\left( n-r \right)!}$. They are also used in probabilities.
Complete step by step answer:
The given multiplication is to be converted to the factorial form. The use for the factorial function is to count how many ways you can choose things from a collection of things.
We know the term $n!$ defines the notion of multiplication of first n natural numbers.
This means $n!=1\times 2\times 3\times ....\times n$.
But the given multiplication $7\times 8\times 9\times 10\times 11\times 12\times 13\times 14\times 15$ does not start from 1.
Therefore, we multiply the terms from 1 to 6 to $7\times 8\times 9\times 10\times 11\times 12\times 13\times 14\times 15$.
We also divide them to balance the number.
So, $7\times 8\times 9\times 10\times 11\times 12\times 13\times 14\times 15=\dfrac{\left( 1\times 2\times ...\times 6 \right)\times \left( 7\times 8\times ......\times 15 \right)}{1\times 2\times ...\times 6}$.
We can see that the numerator is the multiplication of the first 15 natural numbers and the denominator is the multiplication of the first 6 natural numbers.
Therefore, $1\times 2\times ......\times 15=15!$ and $1\times 2\times ......\times 6=6!$.
We get $7\times 8\times 9\times 10\times 11\times 12\times 13\times 14\times 15=\dfrac{15!}{6!}$.
Converting $7\times 8\times 9\times 10\times 11\times 12\times 13\times 14\times 15$ into factorial form we get $\dfrac{15!}{6!}$.
Note: these factorials are mainly used in cases of permutation or combination. In case of combination the simplified form of the mathematical expression ${}^{n}{{C}_{r}}$ is ${}^{n}{{C}_{r}}=\dfrac{n!}{r!\times \left( n-r \right)!}$. In case of permutation the simplified form of the mathematical expression ${}^{n}{{P}_{r}}$ is ${}^{n}{{P}_{r}}=\dfrac{n!}{\left( n-r \right)!}$. They are also used in probabilities.
Recently Updated Pages
A geostationary satellite is a height h above the surface class 11 physics CBSE

The number of different sevendigit numbers that can class 11 maths CBSE

Is silicon Si a metal metalloid or nonmetal Explai class 11 chemistry CBSE

State the reason why carbon can neither form C4 + cations class 11 chemistry CBSE

Compare the functioning of alveoli in the lungs and class 11 biology CBSE

Write an essay on s p d f block elements class 11 chemistry CBSE

Trending doubts
10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

