
How can I convert between molarity and molality?
Answer
543.3k+ views
Hint: [The molar concentration of a solution. Which is expressed as the number of moles of solute per liter of solution. Whereas malolity also the measurement of molar concentration it is the moles of solute per kilogram of a solvent.]
Complete step by step answer:
Formula for molarity:
Concentration $(M)=\dfrac{n}{v}=\dfrac{\text{number of moles}}{\text{volume}}$
Where,
$M=$ molar concentration
$n=$ moles of solute
$v=$ litres of solution.
Unit $=$ moles liter
Formula for molality
Molality $(m)=\dfrac{\text{Number of moles of solute}}{\text{mass of solvent in kilogram}}$
Relation between molarity and morality
$\dfrac{1}{m}=\dfrac{d}{m}=\dfrac{Ms}{1000}$
Where
$m=$ molarity of solution
$M=$ molarity of solution
$d=$ density of solution in g/m
${{M}_{s}}=$ Molar mass of solute
Above we have both the formula for molarity $(M)$ and molarity $(m)$ so we can easily convert by knowing one quantity ester molarity or molality is both the number of moles of solute remains same but in molarity we talking about volume in liter whereas in molality we should have mass of solvent in kilograms. And we also have the relation between molality and molarity in the above formula then by knowing the density of solution in grams per milliliter and molar mass of solute we have the molality or molarity.
Note: Both are the concentration of the solute respect to volume sometimes we have volume in liter and sometimes we have in gram or kilograms when we are talking about the solids then we have molality and when we are talking in liquid manner then we have molarity.
By calculating molarity and modality we can calculate other terms also. These both terms are very important and help to calculate many important quantities in ‘solution part of chemistry.’ When we study about the properties of any solution first we have knowledge about the molarity normality and molality of that solution.
Complete step by step answer:
Formula for molarity:
Concentration $(M)=\dfrac{n}{v}=\dfrac{\text{number of moles}}{\text{volume}}$
Where,
$M=$ molar concentration
$n=$ moles of solute
$v=$ litres of solution.
Unit $=$ moles liter
Formula for molality
Molality $(m)=\dfrac{\text{Number of moles of solute}}{\text{mass of solvent in kilogram}}$
Relation between molarity and morality
$\dfrac{1}{m}=\dfrac{d}{m}=\dfrac{Ms}{1000}$
Where
$m=$ molarity of solution
$M=$ molarity of solution
$d=$ density of solution in g/m
${{M}_{s}}=$ Molar mass of solute
Above we have both the formula for molarity $(M)$ and molarity $(m)$ so we can easily convert by knowing one quantity ester molarity or molality is both the number of moles of solute remains same but in molarity we talking about volume in liter whereas in molality we should have mass of solvent in kilograms. And we also have the relation between molality and molarity in the above formula then by knowing the density of solution in grams per milliliter and molar mass of solute we have the molality or molarity.
Note: Both are the concentration of the solute respect to volume sometimes we have volume in liter and sometimes we have in gram or kilograms when we are talking about the solids then we have molality and when we are talking in liquid manner then we have molarity.
By calculating molarity and modality we can calculate other terms also. These both terms are very important and help to calculate many important quantities in ‘solution part of chemistry.’ When we study about the properties of any solution first we have knowledge about the molarity normality and molality of that solution.
Recently Updated Pages
Which cell organelles are present in white blood C class 11 biology CBSE

What is the molecular geometry of BrF4 A square planar class 11 chemistry CBSE

How can you explain that CCl4 has no dipole moment class 11 chemistry CBSE

Which will undergo SN2 reaction fastest among the following class 11 chemistry CBSE

The values of mass m for which the 100 kg block does class 11 physics CBSE

Why are voluntary muscles called striated muscles class 11 biology CBSE

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Discuss the various forms of bacteria class 11 biology CBSE

Explain zero factorial class 11 maths CBSE

State the laws of reflection of light

Difference Between Prokaryotic Cells and Eukaryotic Cells

Show that total energy of a freely falling body remains class 11 physics CBSE

