
Convert \[7\;{\rm{pm}}\] into \[{\rm{\mu m}}\]
A. \[7 \times {10^{ - 6}}\;{\rm{\mu m}}\]
B. \[14 \times {10^{ - 6}}\;{\rm{\mu m}}\]
C. \[7 \times {10^{ - 3}}\;{\rm{\mu m}}\]
D. \[14 \times {10^{ - 3}}\;{\rm{\mu m}}\]
Answer
579.3k+ views
Hint:
The above problem can be resolved using the concepts and the fundamentals of the unit conversion. The basic unit conversion includes converting the unit of meter to hectometre, decimetre, centimetre, and many more. Similarly, the unit conversion for the picometer into the micrometre is asked in the given problem, which is mathematically calculated by dividing the value with standard form.
Complete step by step solution
We know that 1 picometer (pm) is numerically equal to \[{10^{ - 6}}\] micrometre.
The mathematical expression is given as,
\[1\;{\rm{pm}} = 1\;{\rm{pm}} \times \dfrac{{{{10}^{ - 6}}\;{\rm{\mu m}}}}{{1\;{\rm{pm}}}} = 1 \times {10^{ - 6}}\;{\rm{\mu m}}\]
Now, convert 7 picometer as,
\[7\;{\rm{pm}} = 7\;{\rm{pm}} \times \dfrac{{{{10}^{ - 6}}\;{\rm{\mu m}}}}{{1\;{\rm{pm}}}} = 7 \times {10^{ - 6}}\;{\rm{\mu m}}\]
Therefore, the 7 picometre is equivalent to the \[7 \times {10^{ - 6}}\] micrometres.
Note:
To resolve the given problem, one must be sure about converting the fundamental units into the other forms. The other forms include the centimetre, decimetre, kilometre, for the measurement of the linear dimensions. Moreover, this technique is further utilized to resolve the complex problems of modern physics as well as basic physics.
The above problem can be resolved using the concepts and the fundamentals of the unit conversion. The basic unit conversion includes converting the unit of meter to hectometre, decimetre, centimetre, and many more. Similarly, the unit conversion for the picometer into the micrometre is asked in the given problem, which is mathematically calculated by dividing the value with standard form.
Complete step by step solution
We know that 1 picometer (pm) is numerically equal to \[{10^{ - 6}}\] micrometre.
The mathematical expression is given as,
\[1\;{\rm{pm}} = 1\;{\rm{pm}} \times \dfrac{{{{10}^{ - 6}}\;{\rm{\mu m}}}}{{1\;{\rm{pm}}}} = 1 \times {10^{ - 6}}\;{\rm{\mu m}}\]
Now, convert 7 picometer as,
\[7\;{\rm{pm}} = 7\;{\rm{pm}} \times \dfrac{{{{10}^{ - 6}}\;{\rm{\mu m}}}}{{1\;{\rm{pm}}}} = 7 \times {10^{ - 6}}\;{\rm{\mu m}}\]
Therefore, the 7 picometre is equivalent to the \[7 \times {10^{ - 6}}\] micrometres.
Note:
To resolve the given problem, one must be sure about converting the fundamental units into the other forms. The other forms include the centimetre, decimetre, kilometre, for the measurement of the linear dimensions. Moreover, this technique is further utilized to resolve the complex problems of modern physics as well as basic physics.
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