
Convert \[1Joule\] to \[ergs\] in dimensional analysis.
Answer
510.3k+ views
Hint: First of all, we have to understand the meaning and use of unit joules according to the guidelines of the SI system of units. Joules is the unit of work or energy and this is equal to the Force applied in unit newton through unit meter. Secondly, for dimensional analysis we have to use their dimensions and convert joules to ergs.
Dimensions of joules as well as ergs, since both are the units of energy: \[[{M^1}{L^2}{T^{ - 2}}]\].
Complete step by step solution:
Here, we have to convert joules to ergs as joules is the SI unit of energy and ergs is the CGS unit of energy.
Now, let us use the dimensional formula for joules and ergs as follows:
\[{n_1}joules = {n_2}ergs\] …. \[(1)\]
Let us use dimensions of joules and ergs as:
\[joule = [M_1^1L_1^2T_1^{ - 2}]\] and \[erg = [M_2^1L_2^2T_2^{ - 2}]\]
Using these values in equation \[(1)\] such that:
\[{n_1}[M_1^1L_1^2T_1^{ - 2}] = {n_2}[M_2^1L_2^2T_2^{ - 2}]\]
\[ \Rightarrow {n_2} = {n_1}\frac{{[M_1^1L_1^2T_1^{ - 2}]}}{{[M_2^1L_2^2T_2^{ - 2}]}}\] …. \[(2)\]
\[ \Rightarrow {n_2} = {n_1}{\left[ {\frac{{{M_1}}}{{{M_2}}}} \right]^1}{\left[ {\frac{{{L_1}}}{{{L_2}}}} \right]^2}{\left[ {\frac{{{T_1}}}{{{T_2}}}} \right]^{ - 2}}\]
\[ \Rightarrow {n_2} = 1{\left[ {\frac{{1kg}}{{gm}}} \right]^1}{\left[ {\frac{{1m}}{{1cm}}} \right]^2}{\left[ {\frac{{1s}}{{1s}}} \right]^{ - 2}}\]
\[ \Rightarrow {n_2} = 1{\left[ {\frac{{1000gm}}{{gm}}} \right]^1}{\left[ {\frac{{100cm}}{{1cm}}} \right]^2}{\left[ {\frac{{1s}}{{1s}}} \right]^{ - 2}}\]
\[ \Rightarrow {n_2} = {10^7}(ergs)\] …. \[{\text{(3)}}\]
Now, we know that
\[1{\text{ joule of energy}} = 1{\text{ newton}} \times 1{\text{ meter}}\]
\[{\text{1 erg = 1 dyne}} \times {\text{1 cm}}\]
\[{\text{1 joule = 1}}{{\text{0}}^5}{\text{ dynes }} \times {\text{ 1}}{{\text{0}}^2}{\text{ cm}}\]
\[{\text{1 joule = 1}}{{\text{0}}^7}{\text{ ergs}}\] …. From \[{\text{(3)}}\]
Thus, this is the way to convert \[1Joule\] to \[ergs\] with the help of dimensional analysis. We conclude that \[{\text{1 joule = 1}}{{\text{0}}^7}{\text{ ergs}}\].
Note:
Here, we must know the dimensional formulae of joules and ergs are the same because they are the SI and CGS units respectively of energy and work done. So, it will be easier to convert them from SI to CGS and find the required answer. Also, we have to convert mass and lengths from SI to CGS so that the whole joule can be converted to ergs as we have discussed above.
Dimensions of joules as well as ergs, since both are the units of energy: \[[{M^1}{L^2}{T^{ - 2}}]\].
Complete step by step solution:
Here, we have to convert joules to ergs as joules is the SI unit of energy and ergs is the CGS unit of energy.
Now, let us use the dimensional formula for joules and ergs as follows:
\[{n_1}joules = {n_2}ergs\] …. \[(1)\]
Let us use dimensions of joules and ergs as:
\[joule = [M_1^1L_1^2T_1^{ - 2}]\] and \[erg = [M_2^1L_2^2T_2^{ - 2}]\]
Using these values in equation \[(1)\] such that:
\[{n_1}[M_1^1L_1^2T_1^{ - 2}] = {n_2}[M_2^1L_2^2T_2^{ - 2}]\]
\[ \Rightarrow {n_2} = {n_1}\frac{{[M_1^1L_1^2T_1^{ - 2}]}}{{[M_2^1L_2^2T_2^{ - 2}]}}\] …. \[(2)\]
\[ \Rightarrow {n_2} = {n_1}{\left[ {\frac{{{M_1}}}{{{M_2}}}} \right]^1}{\left[ {\frac{{{L_1}}}{{{L_2}}}} \right]^2}{\left[ {\frac{{{T_1}}}{{{T_2}}}} \right]^{ - 2}}\]
\[ \Rightarrow {n_2} = 1{\left[ {\frac{{1kg}}{{gm}}} \right]^1}{\left[ {\frac{{1m}}{{1cm}}} \right]^2}{\left[ {\frac{{1s}}{{1s}}} \right]^{ - 2}}\]
\[ \Rightarrow {n_2} = 1{\left[ {\frac{{1000gm}}{{gm}}} \right]^1}{\left[ {\frac{{100cm}}{{1cm}}} \right]^2}{\left[ {\frac{{1s}}{{1s}}} \right]^{ - 2}}\]
\[ \Rightarrow {n_2} = {10^7}(ergs)\] …. \[{\text{(3)}}\]
Now, we know that
\[1{\text{ joule of energy}} = 1{\text{ newton}} \times 1{\text{ meter}}\]
\[{\text{1 erg = 1 dyne}} \times {\text{1 cm}}\]
\[{\text{1 joule = 1}}{{\text{0}}^5}{\text{ dynes }} \times {\text{ 1}}{{\text{0}}^2}{\text{ cm}}\]
\[{\text{1 joule = 1}}{{\text{0}}^7}{\text{ ergs}}\] …. From \[{\text{(3)}}\]
Thus, this is the way to convert \[1Joule\] to \[ergs\] with the help of dimensional analysis. We conclude that \[{\text{1 joule = 1}}{{\text{0}}^7}{\text{ ergs}}\].
Note:
Here, we must know the dimensional formulae of joules and ergs are the same because they are the SI and CGS units respectively of energy and work done. So, it will be easier to convert them from SI to CGS and find the required answer. Also, we have to convert mass and lengths from SI to CGS so that the whole joule can be converted to ergs as we have discussed above.
Recently Updated Pages
Why are manures considered better than fertilizers class 11 biology CBSE

Find the coordinates of the midpoint of the line segment class 11 maths CBSE

Distinguish between static friction limiting friction class 11 physics CBSE

The Chairman of the constituent Assembly was A Jawaharlal class 11 social science CBSE

The first National Commission on Labour NCL submitted class 11 social science CBSE

Number of all subshell of n + l 7 is A 4 B 5 C 6 D class 11 chemistry CBSE

Trending doubts
What is meant by exothermic and endothermic reactions class 11 chemistry CBSE

10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

What are Quantum numbers Explain the quantum number class 11 chemistry CBSE

