Question

How do you convert $105$ degrees Fahrenheit to Celsius?

Answer 1

Hint: The degree of intensity of heat in a body is called temperature. Both Fahrenheit and Celsius are the scales to measure temperature of a body. Fahrenheit is denoted as ${}^{0}F$ and Celsius is denoted as ${}^{0}C$.

Complete step by step answer:
We must know the relation between Celsius scale and Fahrenheit scale. This is related as
$F={\displaystyle \frac{9}{5}}C+32$ $\to (i)$
Where, F denotes for Fahrenheit
C denotes for Celsius.
Now, we need to convert 105 degrees Fahrenheit which we can write as $105$ ${}^{0}F$ into degree Celsius ${}^{0}C$, so we have $F=105$ and we need to find the value of $C$.
Put the value of $F=105$ in equation $(i)$
We get,
$105={\displaystyle \frac{9}{5}}C+32$
$\Rightarrow 105-32={\displaystyle \frac{9}{5}}C$
$\Rightarrow {\displaystyle \frac{9}{5}}C=73$
$\Rightarrow C={\displaystyle \frac{73\times 5}{9}}$
$\therefore C=40.5$

Hence, $105$ degree Fahrenheit in to degree Celsius is equal to $40.5$ which can be written as ${40.5}^{0}C$.

Additional information: There’s used to be another important scale which is used to measure temperature of a body and it’s called Rankine denoted as $R$. Rankine scale starts with absolute zero.
Its relation with Celsius scale is given as
$C=(R-491.67)\times {\displaystyle \frac{5}{9}}$
Its relation with Fahrenheit scale is given as:
$32F+459.67=491.67R$.

Note: Water freezes at $0$ degree Celsius and boils at $100$ degree Celsius, while in Fahrenheit, water freezes at $32$ degrees Fahrenheit and boils at $212$ degrees Fahrenheit. You can see that ${}^{0}C$ has $100$ degrees between freezing and boiling point. ${}^{0}F$ has $180$ degrees between these two points.