Question

How do you convert $105$ degrees Fahrenheit to Celsius?

Answer 1

Hint: The degree of intensity of heat in a body is called temperature. Both Fahrenheit and Celsius are the scales to measure temperature of a body. Fahrenheit is denoted as $^0F$ and Celsius is denoted as $^0C$.

Complete step by step answer:
We must know the relation between Celsius scale and Fahrenheit scale. This is related as
$F = \dfrac{9}{5}C + 32$ $ \to (i)$
Where, F denotes for Fahrenheit
C denotes for Celsius.
Now, we need to convert 105 degrees Fahrenheit which we can write as $105$ $^0F$ into degree Celsius $^0C$, so we have $F = 105$ and we need to find the value of $C$.
Put the value of $F = 105$ in equation $(i)$
We get,
$105 = \dfrac{9}{5}C + 32$
$\Rightarrow 105 - 32 = \dfrac{9}{5}C$
$ \Rightarrow \dfrac{9}{5}C = 73$
$\Rightarrow C = \dfrac{{73 \times 5}}{9}$
$\therefore C = 40.5$

Hence, $105$ degree Fahrenheit in to degree Celsius is equal to $40.5$ which can be written as $40.5^0C$.

Additional information: There’s used to be another important scale which is used to measure temperature of a body and it’s called Rankine denoted as $R$. Rankine scale starts with absolute zero.
Its relation with Celsius scale is given as
$C = (R - 491.67) \times \dfrac{5}{9}$
Its relation with Fahrenheit scale is given as:
$32F + 459.67 = 491.67R$.

Note: Water freezes at $0$ degree Celsius and boils at $100$ degree Celsius, while in Fahrenheit, water freezes at $32$ degrees Fahrenheit and boils at $212$ degrees Fahrenheit. You can see that $^0C$ has $100$ degrees between freezing and boiling point. $^0F$ has $180$ degrees between these two points.