Convert 1 radian into a degree minute and second?
Answer
558.3k+ views
Hint: We describe the relation between the degree and radians, two ways to express the angles. We find the relation that 180 degrees is equal to $\pi $ radian. We express the degree value of 1 radian. We use the concept of the unitary system. We also use multiplication for the relation of ${{1}^{\circ }}$ being equal to 60 minutes and 1 minute $\left( {{1}^{'}} \right)$ is equal to 60 seconds $\left( {{1}^{''}} \right)$.
Complete step by step answer:
We need to find the relations between the degree and radians. There are two ways to express the angles. They are degrees and radians. The way to differentiate them is using the degree sign on the angle value.
If the angle is $x$, then it means it’s $x$ radian and if it’s given ${{x}^{\circ }}$, then that means $x$ degree.
The relation between these two units is that 180 degrees is equal to $\pi $ radian. The value of $\pi $ is the usual value where $\pi =3.14$. (approx.)
Therefore, $\pi \text{ rad}={{180}^{\circ }}$. We also know that ${{1}^{\circ }}$ is equal to 60 minutes and 1 minute $\left( {{1}^{'}} \right)$ is equal to 60 seconds $\left( {{1}^{''}} \right)$. We can convert it into radian using the relation where 1 degree is equal to $\dfrac{\pi }{180}$ radian. This gives $x$ degree is equal to $\dfrac{\pi x}{180}$ radian. We get that 1 radian is equal to ${{\left( \dfrac{180}{\pi } \right)}^{\circ }}$.
${{\left( \dfrac{180}{\pi } \right)}^{\circ }}={{\left( 57\dfrac{3}{11} \right)}^{\circ }}$. We now convert \[{{\left( \dfrac{3}{11} \right)}^{\circ }}\] into minutes.
\[{{\left( \dfrac{3}{11} \right)}^{\circ }}={{\left( \dfrac{3}{11}\times 60 \right)}^{'}}={{\left( 16\dfrac{4}{11} \right)}^{'}}\]
We now convert \[{{\left( \dfrac{4}{11} \right)}^{'}}\] into seconds.
\[{{\left( \dfrac{4}{11} \right)}^{'}}={{\left( \dfrac{4}{11}\times 60 \right)}^{''}}={{\left( 21\dfrac{9}{11} \right)}^{''}}\]
Therefore, 1 radian is equal to \[{{57}^{\circ }}{{16}^{'}}{{\left( 21\dfrac{9}{11} \right)}^{''}}\].
Note: Degrees and radians are ways of measuring angles. A radian is equal to the amount an angle would have to be open to capture an arc of the circle's circumference of equal length to the circle's radius.
Complete step by step answer:
We need to find the relations between the degree and radians. There are two ways to express the angles. They are degrees and radians. The way to differentiate them is using the degree sign on the angle value.
If the angle is $x$, then it means it’s $x$ radian and if it’s given ${{x}^{\circ }}$, then that means $x$ degree.
The relation between these two units is that 180 degrees is equal to $\pi $ radian. The value of $\pi $ is the usual value where $\pi =3.14$. (approx.)
Therefore, $\pi \text{ rad}={{180}^{\circ }}$. We also know that ${{1}^{\circ }}$ is equal to 60 minutes and 1 minute $\left( {{1}^{'}} \right)$ is equal to 60 seconds $\left( {{1}^{''}} \right)$. We can convert it into radian using the relation where 1 degree is equal to $\dfrac{\pi }{180}$ radian. This gives $x$ degree is equal to $\dfrac{\pi x}{180}$ radian. We get that 1 radian is equal to ${{\left( \dfrac{180}{\pi } \right)}^{\circ }}$.
${{\left( \dfrac{180}{\pi } \right)}^{\circ }}={{\left( 57\dfrac{3}{11} \right)}^{\circ }}$. We now convert \[{{\left( \dfrac{3}{11} \right)}^{\circ }}\] into minutes.
\[{{\left( \dfrac{3}{11} \right)}^{\circ }}={{\left( \dfrac{3}{11}\times 60 \right)}^{'}}={{\left( 16\dfrac{4}{11} \right)}^{'}}\]
We now convert \[{{\left( \dfrac{4}{11} \right)}^{'}}\] into seconds.
\[{{\left( \dfrac{4}{11} \right)}^{'}}={{\left( \dfrac{4}{11}\times 60 \right)}^{''}}={{\left( 21\dfrac{9}{11} \right)}^{''}}\]
Therefore, 1 radian is equal to \[{{57}^{\circ }}{{16}^{'}}{{\left( 21\dfrac{9}{11} \right)}^{''}}\].
Note: Degrees and radians are ways of measuring angles. A radian is equal to the amount an angle would have to be open to capture an arc of the circle's circumference of equal length to the circle's radius.
Recently Updated Pages
If x a + bt + ct2 where x is in meters and t is in class 11 physics CBSE

A car covers the first half distance between two places class 11 physics CBSE

The resultant of two vectors overrightarrow P and overrightarrow class 11 physics CBSE

Find the value of cos 135 class 11 maths CBSE

A mass M is held in place by an applied force F and class 11 physics CBSE

A solution of glucose in water is labelled as 10 dfracwv class 11 chemistry CBSE

Trending doubts
Find the value of the expression given below sin 30circ class 11 maths CBSE

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

10 examples of friction in our daily life

Proton was discovered by A Thomson B Rutherford C Chadwick class 11 chemistry CBSE

Bond order ofO2 O2+ O2 and O22 is in order A O2 langle class 11 chemistry CBSE

