
Construct an equilateral triangle, given its side = 3 and justify its construction.
Answer
508.8k+ views
Hint: In this particular question use the concept that if all the sides of a triangle are equal than it is an equilateral triangle and in an equilateral triangle all angles are equal to 60 degrees so first draw a line of 3 cm using a ruler then construct the angle of 60 degrees from both the end of this line, so use these concepts to reach the solutions of the questions.
Complete step-by-step answer:
Steps of construction
$\left( i \right)$ Draw of line BC of 3 cm using a ruler as shown in the below figure.
$\left( {ii} \right)$ Now make an arc from both the ends of the line using the compass with pointed end of the compass on point B and C respectively and make an arc with the pencil end as shown below which cut the line BC at point D and E respectively. Consider an appropriate distance in the compass less than half of the distance of the line BC.
$\left( {iii} \right)$ Now with the same distance in the compass mark an arc from point D and E on the previous arcs which cut the arcs at point F and G as shown below.
$\left( {iv} \right)$ Now join points B to F and C to G and extend further so that both the lines cut at the point A, as shown in the below figure.
So ABC is the required equilateral triangle of side 3 cm.
Now as we measure the sides from the ruler we get AB = BC = CA = 3cm.
So we can say this is an equilateral triangle.
So this is the required answer.
Note: Whenever we face such types of questions the key concept we have to remember is that always recall the steps of construction which is stated above, these steps are the basis of the construction, without these steps we cannot draw the equilateral triangle of side 3 cm.
Complete step-by-step answer:
Steps of construction
$\left( i \right)$ Draw of line BC of 3 cm using a ruler as shown in the below figure.

$\left( {ii} \right)$ Now make an arc from both the ends of the line using the compass with pointed end of the compass on point B and C respectively and make an arc with the pencil end as shown below which cut the line BC at point D and E respectively. Consider an appropriate distance in the compass less than half of the distance of the line BC.

$\left( {iii} \right)$ Now with the same distance in the compass mark an arc from point D and E on the previous arcs which cut the arcs at point F and G as shown below.

$\left( {iv} \right)$ Now join points B to F and C to G and extend further so that both the lines cut at the point A, as shown in the below figure.

So ABC is the required equilateral triangle of side 3 cm.
Now as we measure the sides from the ruler we get AB = BC = CA = 3cm.
So we can say this is an equilateral triangle.
So this is the required answer.
Note: Whenever we face such types of questions the key concept we have to remember is that always recall the steps of construction which is stated above, these steps are the basis of the construction, without these steps we cannot draw the equilateral triangle of side 3 cm.
Recently Updated Pages
Express the following as a fraction and simplify a class 7 maths CBSE

The length and width of a rectangle are in ratio of class 7 maths CBSE

The ratio of the income to the expenditure of a family class 7 maths CBSE

How do you write 025 million in scientific notatio class 7 maths CBSE

How do you convert 295 meters per second to kilometers class 7 maths CBSE

Write the following in Roman numerals 25819 class 7 maths CBSE

Trending doubts
Full Form of IASDMIPSIFSIRSPOLICE class 7 social science CBSE

The southernmost point of the Indian mainland is known class 7 social studies CBSE

Convert 200 Million dollars in rupees class 7 maths CBSE

One lakh eight thousand how can we write it in num class 7 maths CBSE

What is meant by Indian Standard Time Why do we need class 7 social science CBSE

List of coprime numbers from 1 to 100 class 7 maths CBSE
