Question

Construct a quadrilateral ABNV where AV=7cm, BA=8cm, BN=10cm, NV=5cm and BV=11cm. Then, the measure of \[\angle NBV\](in degrees) is.

Answer 1

Hint: To solve the type of question mentioned above we will be using all the details properly and will be using rulers, pencil and a compass to draw the quadrilateral ABCD with dimensions and the angels mentioned. We will also use a protractor to draw the lines with that particular angle. Then we will use the protractor to measure \[\angle NBV\](in degrees).

Complete step by step solution:
For starting this type of question we will first be taking a random point in a plain sheet of paper and will be assuming it to be point A of the quadrilateral. Then we will make a straight line of 8 cm horizontally which will give us our 2nd point of quadrilateral that is point B.

Now we know that the distance of our 4th point of quadrilateral V is 7cm from A and 11cm from B, to find this point we will make use of the compass, pencil and ruler. First we will use the compass and take a measurement of 7cm and then we are going to make an arc vertically above point A (as the quadrilateral will be closed figure so to make that happen we will mark that point vertically up from point A), then we are going to do the same with point B by taking measurement of 11cm and making an arc which will intersect the arc made through point A and that intersecting point will become our 4th quadrilateral point V.

Now that we have got our 1st, 2nd and 4th point, by using those points we can use these points to get our 3rd point, from the question we know the distance between BN and VN with those at hand we are going to repeat the same procedure again (the one we used to find out 4th point by using arcs and making them intersect and that intersection will be our 3rd point N).

Now that our quadrilateral is formed we will use the protractor to measure the \[\angle NBV\](in degrees). We will keep the center point of the protector on point B and the center line will be coinciding with line AB then we will see where the other line is coinciding with what value on the protector and we will get the value to be approximately \[{{68}^{\circ }}\]

Note: In this type of formation of diagrams make sure that you have a scale where you can clearly see the numbers and divisions on the number scale, make sure you have properly sharpened pencil so as to make the diagram as accurate as possible and also make sure you have a good compass (easier to work with) and also a protector where each and every division with the centerline of the protector is visible.