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Construct a quadrilateral ABCD in which AB = 3.6 cm , BC = 3.3 cm , AD = 2.7 cm diagonal AC = 4.6 cm and BD = 4 cm

Answer
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Hint: Splitting the quadrilateral into two triangles , first we need to construct one triangle using the compass and scale that by drawing a line segment AB and drawing arcs of required measurement from A and B and that intersection point is marked as C. Now once again let's draw the arcs from and B to get the point D and joining C and D we get the required quadrilateral.

Complete step-by-step answer:
Now lets sketch the rough diagram of the quadrilateral ABCD.
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And we can see that the quadrilateral consists of two triangles ABC and ACD
First lets construct the triangle ABC has all the sides are given
Let's draw a line segment AB of 3.6 cm
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Now we are given AC = 4.6 cm
So place the compass at A and draw an arc with radius 4.6 cm
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And since BC = 3.3 cm
Place the compass at B and draw an arc with radius 3.3 cm intersecting the arc drawn in the previous step and this intersection point is marked as C.
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Draw the lines AC and BC
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Now we are given AD = 2.7 cm
So place the compass at A and draw an arc with radius 2.7 cm just above A
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And since BD = 4 cm
Place the compass at B and draw an arc with radius 4 cm intersecting the arc drawn in the previous step and this intersection point is marked as D
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Draw the lines AD and BD
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And joining CD we get the required quadrilateral.
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Note: A quadrilateral is a polygon which has 4 vertices and 4 sides enclosing 4 angles. The sum of its interior angles is 360 degrees. A quadrilateral, in general, has sides of different lengths and angles of different measures. However, squares, rectangles, etc. are special types of quadrilaterals with some of their sides and angles being equal.