
Consider:
Statement 1 : $\left( p\wedge \sim q \right)\wedge \left( \sim p\wedge q \right)$ is a fallacy.
Statement 2 : $\left( p\to q \right)\leftrightarrow \left( \sim q\to \sim p \right)$ is a tautology.
(1) Statement 1 is true, statement 2 is false.
(2) Statement 1 is false, statement 2 is true.
(3) Statement 1 is true, statement 2 is true: Statement 2 is a correct explanation for statement 1.
(4) Statement 1 is true, statement 2 is true: Statement 2 is not the correct explanation for statement 1.
Answer
578.1k+ views
Hint: Draw a truth table for the expressions in both the statements. For statement 1, check if all the values of the expression are false or not. If they are false, then the statement will be a fallacy, otherwise not. For statement 2, check if all the values of the expression are true or not. If all are true then the statement will be a tautology, otherwise not.
Complete step-by-step solution:
Here, we have been provided with two statements. We have to check whether statement 1 is a fallacy or not and whether statement 2 is a tautology or not. So, let us check them one by one using the truth table.
(i) Statement 1 : $\left( p\wedge \sim q \right)\wedge \left( \sim p\wedge q \right)$ is a fallacy.
Drawing the truth table, we get,
Clearly, we can see that all the values of the expression are false. Hence statement 1 is a fallacy.
(ii) Statement 2 : $\left( p\to q \right)\leftrightarrow \left( \sim q\to \sim p \right)$ is a tautology.
Here, we are going to use the following basic truth table :
Now, drawing the truth table for statement 2, we get,
Clearly, we can see that all the values of the expression are true. Hence, statement 2 is a tautology.
Now, statement 1 and statement 2 are different from each other, so they are independent. Therefore, statement 2 cannot be the correct explanation of statement 1.
Hence, option (4) is the correct answer.
Note: One may note that the above expressions can also be solved without using a truth table. But it will be beneficial for us to solve using the truth table as it will help us in understanding the concept of Boolean algebra more deeply. Further, if we forget the formula, then also by using the basic truth tables, we can solve the above question.
Complete step-by-step solution:
Here, we have been provided with two statements. We have to check whether statement 1 is a fallacy or not and whether statement 2 is a tautology or not. So, let us check them one by one using the truth table.
(i) Statement 1 : $\left( p\wedge \sim q \right)\wedge \left( \sim p\wedge q \right)$ is a fallacy.
Drawing the truth table, we get,
| $p$ | $q$ | $\sim p$ | $\sim q$ | $p\wedge \sim q$ | $\sim p\wedge q$ | $\left( p\wedge \sim q \right)\wedge \left( \sim p\wedge q \right)$ |
| T | T | F | F | F | F | F |
| T | F | F | T | T | F | F |
| F | T | T | F | F | T | F |
| F | F | T | T | F | F | F |
Clearly, we can see that all the values of the expression are false. Hence statement 1 is a fallacy.
(ii) Statement 2 : $\left( p\to q \right)\leftrightarrow \left( \sim q\to \sim p \right)$ is a tautology.
Here, we are going to use the following basic truth table :
| $A$ | $B$ | $A\to B$ | $A\leftrightarrow B$ |
| T | T | T | T |
| T | F | F | F |
| F | T | T | F |
| F | F | T | T |
Now, drawing the truth table for statement 2, we get,
| $p$ | $q$ | $\sim p$ | $\sim q$ | $p\to q$ | $\sim q\to \sim p$ | $\left( p\to q \right)\leftrightarrow \left( \sim q\to \sim p \right)$ |
| T | T | F | F | T | T | T |
| T | F | F | T | F | F | T |
| F | T | T | F | T | T | T |
| F | F | T | T | T | T | T |
Clearly, we can see that all the values of the expression are true. Hence, statement 2 is a tautology.
Now, statement 1 and statement 2 are different from each other, so they are independent. Therefore, statement 2 cannot be the correct explanation of statement 1.
Hence, option (4) is the correct answer.
Note: One may note that the above expressions can also be solved without using a truth table. But it will be beneficial for us to solve using the truth table as it will help us in understanding the concept of Boolean algebra more deeply. Further, if we forget the formula, then also by using the basic truth tables, we can solve the above question.
Recently Updated Pages
Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Discuss the various forms of bacteria class 11 biology CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

10 examples of friction in our daily life

