
What is the concentration of sugar $\left( {{C_{12}}{H_{22}}{O_{11}}} \right)$ in ${\text{mol }}{{\text{L}}^{ - 1}}$. If it's ${\text{20 g}}$ are dissolved in enough water to make a final volume up to ${\text{2 L}}$.
Answer
573.3k+ views
Hint:Concentration of any solution defines the quantity of the solute that is present in a particular quantity of the solvent or the solution. Molarity is the most common unit of concentration, which is equivalent to the number of moles of solute present in ${\text{V}}$ volume of solution in litres.
Complete step by step answer:
Sugar has formula $\left( {{C_{12}}{H_{22}}{O_{11}}} \right)$. So, its molar mass is given by:
= $12{\text{ }} \times {\text{ Mass of C - atom + 22 }} \times {\text{ Mass of H - atom + 11}} \times {\text{ Mass of O - atom}}$
= $11 \times 12 + 22 \times 1 + 11 \times 16$
= ${\text{342 g mo}}{{\text{l}}^{ - 1}}$
So, Molar mass of sugar is ${\text{342 g mo}}{{\text{l}}^{ - 1}}{\text{ }}..........{\text{(1)}}$
Given mass of the sugar is ${\text{20 g }}...........{\text{(2)}}$
Number of moles of sugar = $\dfrac{{{\text{Given mass of sugar}}}}{{{\text{Volume of solution in L}}}}$
From equation ${\text{(1) and (2)}}$,
Or, number of moles of sugar = $\dfrac{{20}}{{342}}{\text{ }}..........{\text{(3)}}$
Here, sugar is the solute, and water is the solution, and it is given that these two solutes and solvent make up a solution of volume ${\text{2 L}}$.
So, volume of the solution in litre is ${\text{2 L }}..........{\text{(4)}}$
We have to calculate the concentration of this solution, which will be equal to the molarity of the solution. Molarity of a solution is given by:
Molarity = $\dfrac{{{\text{Number of moles of solute}}}}{{{\text{Volume of solution in Litre}}}}$
From equation ${\text{(3) and (4)}}$,
$ \Rightarrow $ Molarity of sugar solution ${\text{ = }}\dfrac{{20}}{{342}} \times \dfrac{1}{2}$
$ \Rightarrow $ Molarity of sugar solution = $0 \cdot 029{\text{ mol }}{{\text{L}}^{ - 1}}$
Hence, $0 \cdot 029{\text{ mol }}{{\text{L}}^{ - 1}}$ is the concentration of sugar.
Note:Another unit of concentration is Molality. Because of the similar names, molality, and molarity are mixed together, but they are very different in a way. Molality is the number of moles of solute per kilogram of solvent, whereas, molarity is the number of moles of solute per litre of solution.
Complete step by step answer:
Sugar has formula $\left( {{C_{12}}{H_{22}}{O_{11}}} \right)$. So, its molar mass is given by:
= $12{\text{ }} \times {\text{ Mass of C - atom + 22 }} \times {\text{ Mass of H - atom + 11}} \times {\text{ Mass of O - atom}}$
= $11 \times 12 + 22 \times 1 + 11 \times 16$
= ${\text{342 g mo}}{{\text{l}}^{ - 1}}$
So, Molar mass of sugar is ${\text{342 g mo}}{{\text{l}}^{ - 1}}{\text{ }}..........{\text{(1)}}$
Given mass of the sugar is ${\text{20 g }}...........{\text{(2)}}$
Number of moles of sugar = $\dfrac{{{\text{Given mass of sugar}}}}{{{\text{Volume of solution in L}}}}$
From equation ${\text{(1) and (2)}}$,
Or, number of moles of sugar = $\dfrac{{20}}{{342}}{\text{ }}..........{\text{(3)}}$
Here, sugar is the solute, and water is the solution, and it is given that these two solutes and solvent make up a solution of volume ${\text{2 L}}$.
So, volume of the solution in litre is ${\text{2 L }}..........{\text{(4)}}$
We have to calculate the concentration of this solution, which will be equal to the molarity of the solution. Molarity of a solution is given by:
Molarity = $\dfrac{{{\text{Number of moles of solute}}}}{{{\text{Volume of solution in Litre}}}}$
From equation ${\text{(3) and (4)}}$,
$ \Rightarrow $ Molarity of sugar solution ${\text{ = }}\dfrac{{20}}{{342}} \times \dfrac{1}{2}$
$ \Rightarrow $ Molarity of sugar solution = $0 \cdot 029{\text{ mol }}{{\text{L}}^{ - 1}}$
Hence, $0 \cdot 029{\text{ mol }}{{\text{L}}^{ - 1}}$ is the concentration of sugar.
Note:Another unit of concentration is Molality. Because of the similar names, molality, and molarity are mixed together, but they are very different in a way. Molality is the number of moles of solute per kilogram of solvent, whereas, molarity is the number of moles of solute per litre of solution.
Recently Updated Pages
Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Explain zero factorial class 11 maths CBSE

An example of chemosynthetic bacteria is A E coli B class 11 biology CBSE

State the laws of reflection of light

Name the metals and nonmetals in the first twenty class 11 chemistry CBSE

What is 1s 2s 2p 3s 3p class 11 chemistry CBSE

