Question

Compute the Curves surface area, Surface area and volume for a cylinder with the following dimensions.
a. diameter 2.4cm, height 6.2cm.
b. radius 3cm, height 3.6cm.

Answer 1

Hint: In this problem, we have to find the curved surface area, surface area and the volume of a cylinder whose dimensions are given. We should know the formulas to find the values. We know that the volume of a cylinder is \[\pi {{r}^{2}}h\], surface area of the cylinder is \[2\pi \left( r+h \right)\] and the curved surface area is \[2\pi rh\].

Complete step by step solution:
We know that the given dimensions are,
a. diameter 2.4cm, height 6.2cm.
we also know that the formula for the volume of the cylinder is
Volume of the cylinder = \[\pi {{r}^{2}}h\]
We know that radius is half of the diameter, so
\[r=\dfrac{2.4}{2}=1.2\]cm and we have h = 6.2cm.
We can substitute the above values in volume formula, we get
\[\begin{align}
  & \Rightarrow \dfrac{22}{7}{{\left( 1.2 \right)}^{2}}\left( 6.2 \right) \\
 & \Rightarrow 28.05c{{m}^{3}} \\
\end{align}\]
 We know that the formula for curved surface area is,
Curved surface area of cylinder = \[2\pi rh\].
\[\begin{align}
  & \Rightarrow 2\times \dfrac{22}{7}\left( 1.2 \right)\left( 6.2 \right) \\
 & \Rightarrow 3975c{{m}^{2}} \\
\end{align}\]
We know that the formula for surface area is,
Surface area of cylinder = \[2\pi \left( r+h \right)\].
\[\begin{align}
  & \Rightarrow 2\times \dfrac{22}{7}\left( 1.2+6.2 \right) \\
 & \Rightarrow 46.51c{{m}^{2}} \\
\end{align}\]

Therefore, the volume of cylinder is \[28.05c{{m}^{3}}\], curved surface area of cylinder is \[3975c{{m}^{2}}\] and surface area is \[46.51c{{m}^{2}}\].
b. radius 3cm, height 3.6cm.
we also know that the formula for the volume of the cylinder is
Volume of the cylinder = \[\pi {{r}^{2}}h\]
We know that radius is half of the diameter, so
r = 3cm and we have h = 3.6cm.
We can substitute the above values in volume formula, we get
\[\begin{align}
  & \Rightarrow \dfrac{22}{7}{{\left( 3 \right)}^{2}}\left( 3.6 \right) \\
 & \Rightarrow 101.82c{{m}^{3}} \\
\end{align}\]
 We know that the formula for curved surface area is,
Curved surface area of cylinder = \[2\pi rh\].
\[\begin{align}
  & \Rightarrow 2\times \dfrac{22}{7}\left( 3 \right)\left( 3.6 \right) \\
 & \Rightarrow 67.88c{{m}^{2}} \\
\end{align}\]
We know that the formula for surface area is,
Surface area of cylinder = \[2\pi \left( r+h \right)\].
\[\begin{align}
  & \Rightarrow 2\times \dfrac{22}{7}\left( 3+3.6 \right) \\
 & \Rightarrow 41.48c{{m}^{2}} \\
\end{align}\]

Therefore, the volume of cylinder is \[101.82c{{m}^{3}}\], curved surface area of cylinder is \[67.88c{{m}^{2}}\] and surface area is \[41.48c{{m}^{2}}\].

Note: Students make mistakes while writing the correct formula for the volume, curved surface area and the surface area. We should also remember that radius is half the diameter, so we can divide the given diameter by 2 to get the value of the radius.