
Compressed oxygen is sold at a pressure of 100 atmosphere in a cylinder of 49 litre. The number of moles of oxygen in the cylinder is:
(A) 400
(B) 100
(C) 300
(D) 200
Answer
576.9k+ views
Hint: Ideal gas equation relates the number of moles of any gas with the pressure, temperature and volume of the gas. The equation can be given as
\[PV = nRT\]
where P = pressure of the gas
V = volume of the gas
n = number of moles of gas
R = universal gas constant
T = temperature
Complete Step-by-Step Solution:
We need to find the number of moles of oxygen gas in a given vessel. We will use the ideal gas equation to find the number of moles.
- We know that the ideal gas equation relates the number of moles of any gas with the pressure, temperature and volume of the gas. The equation can be given as
\[PV = nRT\]
Here, pressure of the gas P = 100 atm
Volume of the gas V = 49 L
number of moles = n
Universal gas constant R = 0.0821 L atm/mol K
Temperature = 298 K
Here, the temperature of the gas is not given to us. So, we will assume that the gas is at room temperature which is ${25^ \circ }C$ or 298 K. This temperature corresponds to NTP (Normal temperature and pressure).
So, we can write the above equation as
(100)(49) = (n)(0.0821)(298)
So,
\[n = \dfrac{{100 \times 49}}{{0.0821 \times 298}} = 200\]
Thus, the number of moles of oxygen gas n = 200 moles.
So, the correct answer to the question is (D).
Note: Remember that here we have used L atm/mol K as the unit of universal gas constant R. This is because we want to use Liter as the unit of volume. If we use ${m^3}$ as the unit of volume, then we can use r in unit J/mol K.
\[PV = nRT\]
where P = pressure of the gas
V = volume of the gas
n = number of moles of gas
R = universal gas constant
T = temperature
Complete Step-by-Step Solution:
We need to find the number of moles of oxygen gas in a given vessel. We will use the ideal gas equation to find the number of moles.
- We know that the ideal gas equation relates the number of moles of any gas with the pressure, temperature and volume of the gas. The equation can be given as
\[PV = nRT\]
Here, pressure of the gas P = 100 atm
Volume of the gas V = 49 L
number of moles = n
Universal gas constant R = 0.0821 L atm/mol K
Temperature = 298 K
Here, the temperature of the gas is not given to us. So, we will assume that the gas is at room temperature which is ${25^ \circ }C$ or 298 K. This temperature corresponds to NTP (Normal temperature and pressure).
So, we can write the above equation as
(100)(49) = (n)(0.0821)(298)
So,
\[n = \dfrac{{100 \times 49}}{{0.0821 \times 298}} = 200\]
Thus, the number of moles of oxygen gas n = 200 moles.
So, the correct answer to the question is (D).
Note: Remember that here we have used L atm/mol K as the unit of universal gas constant R. This is because we want to use Liter as the unit of volume. If we use ${m^3}$ as the unit of volume, then we can use r in unit J/mol K.
Recently Updated Pages
Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

Discuss the various forms of bacteria class 11 biology CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

