Complete the reaction $ Xe{F_4} + {O_2}{F_2} \to A + {O_2} $ identify A.
Answer
563.4k+ views
Hint :The unknown product of the reaction must be a compound of xenon with fluorine. For finding the number of xenon and fluorine atoms in that compound try to balance the reaction. The shape of the unknown product is distorted. The product is
Complete Step By Step Answer:
The reactants in this reaction are xenon tetrafluoride and fluorine dioxide. The first binary compound of noble gas to be discovered was xenon tetrafluoride. The reaction which we are dealing with here must produce a xenon compound because xenon is missing in the product side of the reaction.
To find the exact final product, we can use the balancing reaction approach to find what the product is. If we look at the reactant side we have one xenon, six fluorines and two oxygen atoms. Number of oxygen atoms are balanced as there are two oxygen atoms on the product side as well. We need to balance xenon and fluorine atoms and we only have one unknown compound remaining to be found. So we are left with one xenon and six fluorine atoms. If we combine them we come up with $ Xe{F_6} $ which is xenon hexafluoride. Xenon hexafluoride fits completely to be our unknown product because it balances the reaction perfectly.
Hence the final reaction would look like,
$ Xe{F_4} + {O_2}{F_2} \to Xe{F_6} + {O_2} $
So A is $ Xe{F_6} $ .
Note :
Xenon hexafluoride has the shape of a distorted octahedral. This is because of the presence of one lone pair of electrons of xenon. This lone pair causes lone pair – bond pair repulsion which disturbs the natural octahedral geometry of the molecule. Xenon hexafluoride is the strongest fluorinating compound.
Complete Step By Step Answer:
The reactants in this reaction are xenon tetrafluoride and fluorine dioxide. The first binary compound of noble gas to be discovered was xenon tetrafluoride. The reaction which we are dealing with here must produce a xenon compound because xenon is missing in the product side of the reaction.
To find the exact final product, we can use the balancing reaction approach to find what the product is. If we look at the reactant side we have one xenon, six fluorines and two oxygen atoms. Number of oxygen atoms are balanced as there are two oxygen atoms on the product side as well. We need to balance xenon and fluorine atoms and we only have one unknown compound remaining to be found. So we are left with one xenon and six fluorine atoms. If we combine them we come up with $ Xe{F_6} $ which is xenon hexafluoride. Xenon hexafluoride fits completely to be our unknown product because it balances the reaction perfectly.
Hence the final reaction would look like,
$ Xe{F_4} + {O_2}{F_2} \to Xe{F_6} + {O_2} $
So A is $ Xe{F_6} $ .
Note :
Xenon hexafluoride has the shape of a distorted octahedral. This is because of the presence of one lone pair of electrons of xenon. This lone pair causes lone pair – bond pair repulsion which disturbs the natural octahedral geometry of the molecule. Xenon hexafluoride is the strongest fluorinating compound.
Recently Updated Pages
Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Chemistry: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

State and prove Bernoullis theorem class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

Which among the following are examples of coming together class 11 social science CBSE

