
Complete the following table:
Name Molecular formula Condensed structural formula Number of carbon atoms Number of $-C{{H}_{2}}$ units Boiling point Ethene ${{C}_{2}}{{H}_{4}}$ ${{H}_{2}}C=C{{H}_{2}}$ 2 0 -102 Propene _ _ _ _ _ _ _ $C{{H}_{3}}CH=C{{H}_{2}}$ 3 1 -48 1-Butene ${{C}_{4}}{{H}_{8}}$ _ _ _ _ _ _ _ _ _ _ _ _ _ _ 2 -6.5 1-Pentene ${{C}_{5}}{{H}_{10}}$ $C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}CH=C{{H}_{2}}$ 5 _ _ _ _ _ _ +30
(b)- What is meant by homologous series?
(c)- Give an example of alkane which can be represented by the general formula ${{C}_{n}}{{H}_{2n+2}}$.
| Name | Molecular formula | Condensed structural formula | Number of carbon atoms | Number of $-C{{H}_{2}}$ units | Boiling point |
| Ethene | ${{C}_{2}}{{H}_{4}}$ | ${{H}_{2}}C=C{{H}_{2}}$ | 2 | 0 | -102 |
| Propene | _ _ _ _ _ _ _ | $C{{H}_{3}}CH=C{{H}_{2}}$ | 3 | 1 | -48 |
| 1-Butene | ${{C}_{4}}{{H}_{8}}$ | _ _ _ _ _ _ _ _ | _ _ _ _ _ _ | 2 | -6.5 |
| 1-Pentene | ${{C}_{5}}{{H}_{10}}$ | $C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}CH=C{{H}_{2}}$ | 5 | _ _ _ _ _ _ | +30 |
Answer
580.5k+ views
Hint: The general formula of an alkane is ${{C}_{n}}{{H}_{2n+2}}$, so we can find all the members of the alkane group by substituting the value of n in the formula. Methane, ethane, propane, butane, etc are homologous series, and methanol, ethanol, propanol, etc are homologous series.
Complete Solution :
a.)
Propene is the third member of the alkene homologous series and its condensed structural formula given is $C{{H}_{3}}CH=C{{H}_{2}}$, so there are 3 carbon atoms and 6 hydrogen atoms. Therefore the molecular formula is ${{C}_{3}}{{H}_{6}}$.
- The molecular formula of 1-Butene is ${{C}_{4}}{{H}_{8}}$, so its condensed structural formula will be $C{{H}_{3}}C{{H}_{2}}CH=C{{H}_{2}}$. Therefore the number of carbon atoms is 4.
- The condensed formula of 1-Pentene is $C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}CH=C{{H}_{2}}$, so there are three $-C{{H}_{2}}$ units.
So the complete table will be:
(b)- A homologous series is the family or group of organic compounds that contain certain compounds having the same functional group; there is gradation in the physical properties but their chemical properties are similar. Methane, ethane, propane, butane, etc are homologous series, and methanol, ethanol, propanol, etc are homologous series.
(c)- The general formula of an alkane is ${{C}_{n}}{{H}_{2n+2}}$, so we can find all the members of the alkane group by substituting the value of n in the formula. For example, when we put the value of n as 3, then the formula will be ${{C}_{3}}{{H}_{8}}$ and this compound is propane.
Note: The successive group in a homologous series must have a difference of $-C{{H}_{2}}$ group. The general method of preparation in a homologous series must be the same. The melting point of the homologous series increases as the carbon atoms increase in a straight chain.
Complete Solution :
a.)
| Name | Molecular formula | Condensed structural formula | Number of carbon atoms | Number of $-C{{H}_{2}}$ units | Boiling point |
| Ethene | ${{C}_{2}}{{H}_{4}}$ | ${{H}_{2}}C=C{{H}_{2}}$ | 2 | 0 | -102 |
| Propene | _ _ _ _ _ _ _ | $C{{H}_{3}}CH=C{{H}_{2}}$ | 3 | 1 | -48 |
| 1-Butene | ${{C}_{4}}{{H}_{8}}$ | _ _ _ _ _ _ _ _ | _ _ _ _ _ _ | 2 | -6.5 |
| 1-Pentene | ${{C}_{5}}{{H}_{10}}$ | $C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}CH=C{{H}_{2}}$ | 5 | _ _ _ _ _ _ | +30 |
Propene is the third member of the alkene homologous series and its condensed structural formula given is $C{{H}_{3}}CH=C{{H}_{2}}$, so there are 3 carbon atoms and 6 hydrogen atoms. Therefore the molecular formula is ${{C}_{3}}{{H}_{6}}$.
- The molecular formula of 1-Butene is ${{C}_{4}}{{H}_{8}}$, so its condensed structural formula will be $C{{H}_{3}}C{{H}_{2}}CH=C{{H}_{2}}$. Therefore the number of carbon atoms is 4.
- The condensed formula of 1-Pentene is $C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}CH=C{{H}_{2}}$, so there are three $-C{{H}_{2}}$ units.
So the complete table will be:
| Name | Molecular formula | Condensed structural formula | Number of carbon atoms | Number of $-C{{H}_{2}}$ units | Boiling point |
| Ethene | ${{C}_{2}}{{H}_{4}}$ | ${{H}_{2}}C=C{{H}_{2}}$ | 2 | 0 | -102 |
| Propene | ${{C}_{3}}{{H}_{6}}$ | $C{{H}_{3}}CH=C{{H}_{2}}$ | 3 | 1 | -48 |
| 1-Butene | ${{C}_{4}}{{H}_{8}}$ | $C{{H}_{3}}C{{H}_{2}}CH=C{{H}_{2}}$ | 4 | 2 | -6.5 |
| 1-Pentene | ${{C}_{5}}{{H}_{10}}$ | $C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}CH=C{{H}_{2}}$ | 5 | 3 | +30 |
(b)- A homologous series is the family or group of organic compounds that contain certain compounds having the same functional group; there is gradation in the physical properties but their chemical properties are similar. Methane, ethane, propane, butane, etc are homologous series, and methanol, ethanol, propanol, etc are homologous series.
(c)- The general formula of an alkane is ${{C}_{n}}{{H}_{2n+2}}$, so we can find all the members of the alkane group by substituting the value of n in the formula. For example, when we put the value of n as 3, then the formula will be ${{C}_{3}}{{H}_{8}}$ and this compound is propane.
Note: The successive group in a homologous series must have a difference of $-C{{H}_{2}}$ group. The general method of preparation in a homologous series must be the same. The melting point of the homologous series increases as the carbon atoms increase in a straight chain.
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