Question

Complete the following reaction:
\[Zn+NaOH\to \]

Answer 1

Hint: To answer this question we should know that acids react with most metals to form a salt and hydrogen gas. For example, zinc metal reacts with hydrochloric acid producing zinc chloride and hydrogen gas. To answer this question, we should know that metals also react with bases.

Complete step by step answer:
> To answer this question we should know that acid and base react with metals. As we know that acids react with most metals to form a salt and hydrogen gas. As we know that, metals that are more active than acids can undergo a single displacement reaction. For example, zinc metal reacts with hydrochloric acid producing zinc chloride and hydrogen gas.
\[Zn+2HCl\to ZnC{{l}_{2}}+{{H}_{2}}\]
> And we should know that base also reacts with metals. Bases react with metals like zinc to produce hydrogen gas. For example, sodium hydroxide reacts with zinc and water to form sodium zincate and hydrogen gas. The presence of hydrogen gas is confirmed by a pop sound that is produced by hydrogen gas when it comes in contact with fire.
\[Zn+2HCl\to ZnC{{l}_{2}}+{{H}_{2}}\]\[Zn+2NaOH\to N{{a}_{2}}Zn{{O}_{2}}+{{H}_{2}}\]
> We should know that in the salt formed by the reaction between a base and a metal, the metal is present as a part of the negative ion. In the sodium zincate salt (\[N{{a}_{2}}Zn{{O}_{2}}\]), the zinc metal is present as a part of the negative ion, zincate ion (\[Zn{{O}_{2}}^{2-}\])

Note: We should now know about the neutralization reaction. When we mix an acid and base, water and a salt are the products. Salts are ionic compounds containing a positive ion other than and a negative ion other than the hydroxide ion. Double displacement reactions of this type are called neutralization reactions.
Sodium chloride (common salt) and water are formed when hydrochloric acid reacts with sodium hydroxide (a strong base).
\[HCl\text{ }+\text{ }NaOH\to NaCl\text{ }+\text{ }{{H}_{2}}O\]
Sodium sulphate and water are formed when sulphuric acid reacts with sodium hydroxide (a base). \[{{H}_{2}}S{{O}_{4}}\text{ }+\text{ }2NaOH\to N{{a}_{2}}S{{O}_{4}}+2{{H}_{2}}O\]