Question

Complete the following reaction
$C{l_2}{O_6} + NaOH \to $
This question has multiple correct options.
A. $NaCl{O_4}$
B.$NaOCl$
C. $NaCl{O_2}$
D. $NaCl{O_3}$

Answer 1

Hint: A chemical equation is a symbolically interpreted chemical reaction that uses symbols and formulae to describe the reactant and product entities on the left and right, respectively. A chemical equation is made up of the chemical formulas of the reactants (the starting substances) and the chemical formulas of the products (substances formed in the chemical reaction). The two are separated by an arrow symbol, and each individual substance's chemical formula is separated from the others by a plus sign.

Complete answer: A balanced chemical equation is one in which the number of each form of atom on both sides of the equation is equal. Subscripts are a part of the chemical formulas of the reactants and products that signify the number of atoms in the element before them.
$C{l_2}{O_6}$ is a chlorine oxoacid in which the halogen is at its most oxidised state of \[ + 7\]. Chlorine heptoxide \[\left( {C{l_2}{O_7}} \right)\] is the anhydride of perchloric acid. Perchloric acid is formed when chlorine heptoxide dissolves in water. Of all known oxides, it should be the most acidic.
Now, for the given equation,
$C{l_2}{O_6} + 2NaOH \to NaCl{O_3} + NaCl{O_4} + {H_2}O$
So, the correct options are: D. $NaCl{O_3}$ and A. $NaCl{O_4}$

Note:
The electrons in $C{l_2}{O_6}$ are paired. \[Cl - Cl\] bond splits in liquid state or aqueous solution, releasing one unpaired electron. As a result, the diamagnetic structure of $C{l_2}{O_6}$ transforms into a paramagnetic nature in \[Cl{O_3}.\]