Question

Complete the following reaction.
\[C{{H}_{3}}C{{H}_{2}}Br+KCN\to \]

Answer 1

Hint: Alkyl halides generally undergo substitution reactions with other chemicals. The halide which is present in the alkyl halides is going to take the electrons and make the hydrocarbon chain as electron deficient. Due to this alkyl halides are more reactive towards the nucleophilic substitution reactions.

Complete answer:
- In the question it is asked to complete the given chemical reaction.
- The given reaction is as follows.
\[C{{H}_{3}}C{{H}_{2}}Br+KCN\to \]
- We have to find the product which is going to be formed in the above chemical reaction.
- In the given chemical reaction the reactants are ethyl bromide and potassium cyanide.
- The alkyl halides undergo nucleophilic substitution reaction due to the presence of the electron deficient hydrocarbon chain.
- The potassium cyanide contains cyanide ($C{{N}^{-}}$ ), it is a strong nucleophile (Nucleus loving).
- Then we can call the given chemical reaction a substitution chemical reaction.
- We can complete the given chemical reaction by using the above knowledge.
- The complete chemical reaction is as follows.
\[C{{H}_{3}}C{{H}_{2}}Br+KCN\to C{{H}_{3}}C{{H}_{2}}CN+KBr\]
- In the above chemical reaction one mole of ethyl bromide is going to react with one mole of potassium cyanide and forms one mole of ethyl cyanide and the one mole of potassium bromide as the products.

Note:
Nucleophilic substitution reactions are two types and they are Unimolecular substitution reaction and bi molecular substitution chemical reaction. These two types are based on the number of chemical reactions that are going to involve the rate determining step of the chemical step.