Question

Complete the following chemical reaction equation:
(i)$P{{H}_{3}}+HgC{{l}_{2}}\to $
(ii) $PC{{l}_{3}}+{{H}_{2}}O(excess)\to $

Answer 1

Hint: The chemical $P{{H}_{3}}$ is called phosphine and it is weakly basic in nature. The compound $HgC{{l}_{2}}$ is called mercuric chloride. Generally phosphine chemical is going to absorb on the surface of the metallic derivatives and forms ${{M}_{3}}{{P}_{2}}$ compound as the product.

Complete answer:
- In the question it is asked to complete the given chemical reactions.
- The first given chemical reaction is as follows.
\[P{{H}_{3}}+HgC{{l}_{2}}\to \]
- We know that phosphine is going to form a compound by reacting with copper sulphate and forms a product like $C{{u}_{3}}{{P}_{2}}$ .
- The chemical reaction of phosphine with copper sulphate is as follows.
\[2P{{H}_{3}}+3CuS{{O}_{4}}\to C{{u}_{3}}{{P}_{2}}+3{{H}_{2}}S{{O}_{4}}\]
- Now we can complete the given chemical reaction by taking the above chemical reaction as an example.
$2P{{H}_{3}}+3HgC{{l}_{2}}\to \underset{Mercuric\text{ }phosphide}{\mathop{H{{g}_{3}}{{P}_{2}}}}\,+6HCl$
- In the above chemical reaction two moles of phosphine is going to react with 3 moles of mercuric chloride and forms one moles of mercuric phosphide and 6 moles of hydrochloric acid as the products.
- Coming to the given second chemical reaction.
\[PC{{l}_{3}}+{{H}_{2}}O(excess)\to \]
- We know that phosphorus trichloride reacts with water and forms phosphorous acid as the product.
- The chemical reaction of phosphorus trichloride with water is as follows.
 \[PC{{l}_{3}}+3{{H}_{2}}O\to {{H}_{3}}P{{O}_{3}}+3HCl\]
- In the above chemical reaction one mole of phosphorus trichloride with 3 moles of water forms phosphorus acid and 3 moles of hydrochloric acid as the products.

Note:
In both the chemical reaction phosphorus derivative is going to react different chemicals and finally after the completion of the chemical reaction acids are commonly formed in both the Chemical reactions.