Compare XXII__12 (using >,<,=)
A. >
B. <
C. =
D. None
Answer
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Hint: In this question, we have to find a comparison between two numbers out of which one is given in Roman numerals and the other in Hindu Arabic numerals. For this, we will first convert the Roman numeral to Hindu Arabic numeral and then compare.
Complete step by step answer:
Here we have to compare between XXII, 12. For this, we need to convert Roman numeral to Hindu Arabic numeral.
Let us first understand the rules of writing numerals. There is a total of seven alphabets that are used to write Roman numerals which are I(1), V(5), X(10), L(50), C(100), D(500), and M(1000).
Rule 1: The Roman digits I, X, and C are repeated up to three times in succession to form a number. Example: XXX = 10+10+10 = 30.
Rule 2: When a digit of lower value is written to the left of the digits of higher value, the value of digits is subtracted. Example: XL = (50-10) = 40.
Rule 3: When a digit of lower value is written to the right of the digit of higher value, the values of the digit are added. Example: XV = 10+5 = 15.
Here we have to convert XXII to Hindu Arabic numeral. II are two repeated digits, so they will be added, we get II = 1+1 = 2. Similarly, XX will be added, XX = 10+10 = 20. Now I is smaller than X and written to the right side so values will be added. Hence XXII = 10+10+1+1 = 22.
Now our comparison is like this: 22__12.
As we know 22 is greater than 12, so we will use that 22 is greater than (>) 12.
So 22 > 12.
Hence option A is the correct answer.
Note:
Rules should be followed carefully while converting Roman numerals to Hindu Arabic numerals or vice versa. Students often get confused between the sign of less than (<) and greater than (>). Keep in mind to use the opened side of the symbol towards the bigger number.
Complete step by step answer:
Here we have to compare between XXII, 12. For this, we need to convert Roman numeral to Hindu Arabic numeral.
Let us first understand the rules of writing numerals. There is a total of seven alphabets that are used to write Roman numerals which are I(1), V(5), X(10), L(50), C(100), D(500), and M(1000).
Rule 1: The Roman digits I, X, and C are repeated up to three times in succession to form a number. Example: XXX = 10+10+10 = 30.
Rule 2: When a digit of lower value is written to the left of the digits of higher value, the value of digits is subtracted. Example: XL = (50-10) = 40.
Rule 3: When a digit of lower value is written to the right of the digit of higher value, the values of the digit are added. Example: XV = 10+5 = 15.
Here we have to convert XXII to Hindu Arabic numeral. II are two repeated digits, so they will be added, we get II = 1+1 = 2. Similarly, XX will be added, XX = 10+10 = 20. Now I is smaller than X and written to the right side so values will be added. Hence XXII = 10+10+1+1 = 22.
Now our comparison is like this: 22__12.
As we know 22 is greater than 12, so we will use that 22 is greater than (>) 12.
So 22 > 12.
Hence option A is the correct answer.
Note:
Rules should be followed carefully while converting Roman numerals to Hindu Arabic numerals or vice versa. Students often get confused between the sign of less than (<) and greater than (>). Keep in mind to use the opened side of the symbol towards the bigger number.
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