
What is the colour of the precipitate formed by the addition of KI to Pb salt in water?
(A) Yellow
(B) Black
(C) White
(D) Red
Answer
545.4k+ views
Hint: $ \text{Pb}{{\left( \text{N}{{\text{o}}_{3}} \right)}_{2}}+2\text{KI}\to \text{Pb}{{\text{I}}_{2}}+2\text{KN}{{\text{o}}_{3}} $ reaction. Potassium metal is soft and white with a silver luster, has a low melting point, and is a good conductor of heat and electricity. Potassium imparts a vapour that is green.
Complete step by step Solution
$ \begin{align}
& \text{Pb}{{\left( \text{N}{{\text{o}}_{3}} \right)}_{2}}+2\text{KI}\to \text{Pb}{{\text{I}}_{2}}+2\text{KN}{{\text{o}}_{3}} \\
& \\
\end{align} $
Where $ \text{Pb}{{\text{I}}_{2}} $ precipitate is yellow
The reaction between Pb and KI results in the formation of $ \text{Pb}{{\text{I}}_{2}} $ , which is yellow in colour.
So option A is correct answer.
Additional information
Phosphorus is a chemical element with the symbol P and atomic number15. Elemental phosphorus exists in two major forms, white phosphorus and red phosphorus, but because it is highly reactive, phosphorus is never found as a free element on Earth.
Potassium metal is soft and white with a silver luster, has a low melting point, and is a good conductor of heat and electricity. Potassium imparts a vapour that is green.
Iodine is a chemical element with the symbol I and atomic number 53. The heaviest of the stable halogens, it exists as a lustrous, purple black non-metallic solid at standard conditions that melts to form a deep violet liquid at 114 degrees Celsius and boils to a violet gas at 184 degrees Celsius.
Note
Double displacement reaction
As positive and negative radicals exchanged
$ \text{P}{{\text{b}}^{+2}}\text{No}_{3}^{-1}2{{\text{k}}^{+1}}2{{\text{I}}^{-1}}\to \text{Pb}{{\text{I}}_{2}}+2\text{KN}{{\text{o}}_{3}} $
$ \begin{align}
& \text{Cr(OH}{{\text{)}}_{3}}=\text{ Green} \\
& \\
\end{align} $
$ \text{Fe(OH}{{\text{)}}_{2}}=\text{Green} $
$ \text{Fe(OH}{{\text{)}}_{3}}=\text{Brown} $
$ \text{Zn}{{\left( \text{OH} \right)}_{2}}=\text{ White} $
AgBr = yellow
Agl = yellow
Precipitates are insoluble ionic solid products of a reaction, formed when certain cations and anions combine in an aqueous solution .The determining factors of the formation of a precipitate can vary.
The insoluble salt that falls out of solution is known as the precipitate, hence the reaction name.
Complete step by step Solution
$ \begin{align}
& \text{Pb}{{\left( \text{N}{{\text{o}}_{3}} \right)}_{2}}+2\text{KI}\to \text{Pb}{{\text{I}}_{2}}+2\text{KN}{{\text{o}}_{3}} \\
& \\
\end{align} $
Where $ \text{Pb}{{\text{I}}_{2}} $ precipitate is yellow
The reaction between Pb and KI results in the formation of $ \text{Pb}{{\text{I}}_{2}} $ , which is yellow in colour.
So option A is correct answer.
Additional information
Phosphorus is a chemical element with the symbol P and atomic number15. Elemental phosphorus exists in two major forms, white phosphorus and red phosphorus, but because it is highly reactive, phosphorus is never found as a free element on Earth.
Potassium metal is soft and white with a silver luster, has a low melting point, and is a good conductor of heat and electricity. Potassium imparts a vapour that is green.
Iodine is a chemical element with the symbol I and atomic number 53. The heaviest of the stable halogens, it exists as a lustrous, purple black non-metallic solid at standard conditions that melts to form a deep violet liquid at 114 degrees Celsius and boils to a violet gas at 184 degrees Celsius.
Note
Double displacement reaction
As positive and negative radicals exchanged
$ \text{P}{{\text{b}}^{+2}}\text{No}_{3}^{-1}2{{\text{k}}^{+1}}2{{\text{I}}^{-1}}\to \text{Pb}{{\text{I}}_{2}}+2\text{KN}{{\text{o}}_{3}} $
$ \begin{align}
& \text{Cr(OH}{{\text{)}}_{3}}=\text{ Green} \\
& \\
\end{align} $
$ \text{Fe(OH}{{\text{)}}_{2}}=\text{Green} $
$ \text{Fe(OH}{{\text{)}}_{3}}=\text{Brown} $
$ \text{Zn}{{\left( \text{OH} \right)}_{2}}=\text{ White} $
AgBr = yellow
Agl = yellow
Precipitates are insoluble ionic solid products of a reaction, formed when certain cations and anions combine in an aqueous solution .The determining factors of the formation of a precipitate can vary.
The insoluble salt that falls out of solution is known as the precipitate, hence the reaction name.
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