
When \[C{O_2}\left( g \right)\] is passed over red-hot coke it partially gets reduced to \[CO\left( g \right)\]. Upon passing \[0.5\] litre of \[C{O_2}\left( g \right)\]over red-hot coke, the total volume of the gases increased to \[700mL\]. The composition of the gaseous mixture at STP is:
A.\[Co = 200mL:CO = 500mL\]
B.\[CO = 350mL:CO = 350mL\]
C.\[CO = 0.0mL:CO{\text{ = }}700mL\]
D.\[CO = 300mL;CO = 400ml\]
Answer
508.2k+ views
Hint: We know that Carbon dioxide, a boring gas having a weak sharp scent and an acrid taste. It is quite possibly the main ozone depleting substance connected to an Earth-wide temperature boost, however it is a minor segment of Earth's environment shaped in burning of carbon-containing materials, in maturation, and in breath of creatures and utilized by plants in the photosynthesis of sugars. The presence of the gas in the environment keeps a portion of the brilliant energy obtained by Earth from being gotten back to space, along these lines creating the purported nursery impact. Modernly, it is recuperated for various different applications from pipe gases, as a result of the planning of hydrogen for the blend of smelling salts, from limekilns, and from different sources.
Complete answer:
The balanced chemical reaction equation is,
\[C{O_2}\left( g \right) + C\left( s \right) \to 2CO\left( g \right)\]
The amount of carbon dioxide passing is\[0.5L\].
The total volume is \[700ml = 0.7L\]
Calculation:
\[\left( {0.5 - x} \right) + \left( {2x} \right) = 0.7\]
\[0.5 + x = 0.7\]
\[x = 0.2L{\text{ }} = {\text{ }}200ml\]
\[C{O_2}\left( g \right) = 0.5x = 0.5 - 0.2 = 300ml\]
\[CO\left( g \right) = 2x = 0.2 = 0.4 = 400ml\]
Hence option D is correct.
Note:
At temperatures of \[1000^\circ C\] or more, coke carbon responds with carbon dioxide to create carbon monoxide, gasifying the coke all the while. This debilitates the coke structure making it separate inside the heater under mechanical pressure. Various hot strength tests have been created to test the powerlessness of coke to debase in the durable and dynamic coke zones of the impact heater. Similarly as with the cool strength tests, all hot strength tests will in general be varieties upon a typical subject. Uncover a characterized mass and size part of coke to a hot environment containing carbon dioxide for a characterized timeframe. After opening the level of weight reduction is resolved and the coke is tumbled in drum and screened to decide the level of size decrease which happens.
Complete answer:
The balanced chemical reaction equation is,
\[C{O_2}\left( g \right) + C\left( s \right) \to 2CO\left( g \right)\]
The amount of carbon dioxide passing is\[0.5L\].
The total volume is \[700ml = 0.7L\]
Calculation:
\[\left( {0.5 - x} \right) + \left( {2x} \right) = 0.7\]
\[0.5 + x = 0.7\]
\[x = 0.2L{\text{ }} = {\text{ }}200ml\]
\[C{O_2}\left( g \right) = 0.5x = 0.5 - 0.2 = 300ml\]
\[CO\left( g \right) = 2x = 0.2 = 0.4 = 400ml\]
Hence option D is correct.
Note:
At temperatures of \[1000^\circ C\] or more, coke carbon responds with carbon dioxide to create carbon monoxide, gasifying the coke all the while. This debilitates the coke structure making it separate inside the heater under mechanical pressure. Various hot strength tests have been created to test the powerlessness of coke to debase in the durable and dynamic coke zones of the impact heater. Similarly as with the cool strength tests, all hot strength tests will in general be varieties upon a typical subject. Uncover a characterized mass and size part of coke to a hot environment containing carbon dioxide for a characterized timeframe. After opening the level of weight reduction is resolved and the coke is tumbled in drum and screened to decide the level of size decrease which happens.
Recently Updated Pages
Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

Discuss the various forms of bacteria class 11 biology CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

