
Cinnabar $\left( {HgS} \right)$ is heated in air, it is first converted into _______ which is then reduced to ______ on further heating.
A.$HgO$, ${\text{Hg}}$
B.$HgO$, ${\text{H}}{{\text{g}}_2}O$
C.$H{g_2}O$, ${\text{Hg}}$
D.$H{g_2}O$, ${\text{HgO}}$
Answer
510.6k+ views
Hint: We have to know that the cinnabar has been found in areas around the world, ordinarily close to the world's surface in spaces of moderate volcanic movement. It will in general be related with underground aquifers, kept by superheated water weighed down with components like sulfur and mercury.
Complete answer:
We have to know that, the refining normal mercury sulfide (cinnabar) is finished by simmering the mineral in a surge of air or potentially oxygen. Results of these reactions are sulfur dioxide gas and mercury fumes. Therefore, the balanced chemical equation are given below,
$2HgS + 3{O_2}\xrightarrow{\Delta }2HgO + 2S{O_2}$
Where, the $S{O_2}$ is disintegrated in water to create sulfurous corrosive which can without much of a stretch be changed over to sulfuric corrosive. The mercury fume is effectively dense by cooling the flood of gases underneath the vaporization temperature of mercury. I assume if overabundant oxygen is utilized, a portion of the mercury fume will be oxidized to $HgO$ .
The balanced chemical equation of the above reaction has to be given below,
$2HgO\xrightarrow{\Delta }2Hg + {O_2}$
Yet, I don't have the foggiest idea what modern reason that would serve since mercuric oxide is utilized in more modest amounts than mercury metal and it's easy to make the oxide from the metal once you have the last mentioned.
Therefore, the correct option is (A).
Note:
We have to know that, the cinnabar is utilized for shading paints and as one of red shading specialists utilized in tattoo colors. Around forty conventional chinese drugs contain some cinnabar as indicated by pharmacopeia of china, and it is the significant wellspring of mercury found in customary prescriptions.
Complete answer:
We have to know that, the refining normal mercury sulfide (cinnabar) is finished by simmering the mineral in a surge of air or potentially oxygen. Results of these reactions are sulfur dioxide gas and mercury fumes. Therefore, the balanced chemical equation are given below,
$2HgS + 3{O_2}\xrightarrow{\Delta }2HgO + 2S{O_2}$
Where, the $S{O_2}$ is disintegrated in water to create sulfurous corrosive which can without much of a stretch be changed over to sulfuric corrosive. The mercury fume is effectively dense by cooling the flood of gases underneath the vaporization temperature of mercury. I assume if overabundant oxygen is utilized, a portion of the mercury fume will be oxidized to $HgO$ .
The balanced chemical equation of the above reaction has to be given below,
$2HgO\xrightarrow{\Delta }2Hg + {O_2}$
Yet, I don't have the foggiest idea what modern reason that would serve since mercuric oxide is utilized in more modest amounts than mercury metal and it's easy to make the oxide from the metal once you have the last mentioned.
Therefore, the correct option is (A).
Note:
We have to know that, the cinnabar is utilized for shading paints and as one of red shading specialists utilized in tattoo colors. Around forty conventional chinese drugs contain some cinnabar as indicated by pharmacopeia of china, and it is the significant wellspring of mercury found in customary prescriptions.
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