
How many chords can be drawn through 21 points on a circle?
Answer
553.8k+ views
Hint:
Here, we will use the concept of chord of a circle. A chord is defined as a line segment formed by joining any two distinct points lying on the circle. It is formed by joining any 2 of the 21 points lying on the circle. We will use the formula for combinations to find the required number of chords.
Formula Used: The number of ways in which the \[n\] objects can be placed in \[r\] spaces, where order of objects is not important, can be found using the formula for combinations \[{}^n{C_r} = \dfrac{{n!}}{{r!\left( {n - r} \right)!}}\].
Complete step by step solution:
We will use combinations to find the number of chords that we can draw through 21 points on a circle.
The number of ways in which the \[n\] objects can be placed in \[r\] spaces, where order of objects is not important, can be found using the formula for combinations \[{}^n{C_r} = \dfrac{{n!}}{{r!\left( {n - r} \right)!}}\].
The number of chords that can be formed using the 21 points, taking 2 points at a time, is given by \[{}^{21}{C_2}\].
Substituting \[n = 21\] and \[r = 2\] in the formula for combinations, we get
Number of chords that can be formed using the 21 points \[ = {}^{21}{C_2} = \dfrac{{21!}}{{2!\left( {21 - 2} \right)!}}\]
We know that \[n!\] can be written as \[n\left( {n - 1} \right)!\] or \[n\left( {n - 1} \right)\left( {n - 2} \right)!\].
Rewriting \[21!\] as \[21\left( {21 - 1} \right)\left( {21 - 2} \right)!\], we get
\[ \Rightarrow \]Number of chords that can be formed using the 21 points \[ = {}^{21}{C_2} = \dfrac{{21\left( {21 - 1} \right)\left( {21 - 2} \right)!}}{{2!\left( {21 - 2} \right)!}}\]
Simplifying the expression, we get
\[ \Rightarrow \]Number of chords that can be formed using the 21 points \[ = \dfrac{{21 \times 20 \times 19!}}{{2 \times 1 \times 19!}}\]
Therefore, we get
\[ \Rightarrow \]Number of chords that can be formed using the 21 points \[ = 21 \times 10\]
Multiplying 21 by 10, we get
\[ \Rightarrow \] Number of chords that can be formed using the 21 points \[ = 210\]
Therefore, the number of chords that can be formed using the 21 points lying on the circle is 210 chords.
Note:
We used combinations instead of permutations to find the number of chords that can be formed using the points on the circle. A chord is formed using 2 points. Suppose two of the 21 points are A and B. Now, if A is joined to B, the chord is AB. If B is joined to A, the chord is BA. However, BA and AB are the same. If we used permutations, the chords AB and BA will be counted as 2 different chords. Therefore, we have used combinations since it does not matter which point is the initial points and which point is the terminal point.
Here, we will use the concept of chord of a circle. A chord is defined as a line segment formed by joining any two distinct points lying on the circle. It is formed by joining any 2 of the 21 points lying on the circle. We will use the formula for combinations to find the required number of chords.
Formula Used: The number of ways in which the \[n\] objects can be placed in \[r\] spaces, where order of objects is not important, can be found using the formula for combinations \[{}^n{C_r} = \dfrac{{n!}}{{r!\left( {n - r} \right)!}}\].
Complete step by step solution:
We will use combinations to find the number of chords that we can draw through 21 points on a circle.
The number of ways in which the \[n\] objects can be placed in \[r\] spaces, where order of objects is not important, can be found using the formula for combinations \[{}^n{C_r} = \dfrac{{n!}}{{r!\left( {n - r} \right)!}}\].
The number of chords that can be formed using the 21 points, taking 2 points at a time, is given by \[{}^{21}{C_2}\].
Substituting \[n = 21\] and \[r = 2\] in the formula for combinations, we get
Number of chords that can be formed using the 21 points \[ = {}^{21}{C_2} = \dfrac{{21!}}{{2!\left( {21 - 2} \right)!}}\]
We know that \[n!\] can be written as \[n\left( {n - 1} \right)!\] or \[n\left( {n - 1} \right)\left( {n - 2} \right)!\].
Rewriting \[21!\] as \[21\left( {21 - 1} \right)\left( {21 - 2} \right)!\], we get
\[ \Rightarrow \]Number of chords that can be formed using the 21 points \[ = {}^{21}{C_2} = \dfrac{{21\left( {21 - 1} \right)\left( {21 - 2} \right)!}}{{2!\left( {21 - 2} \right)!}}\]
Simplifying the expression, we get
\[ \Rightarrow \]Number of chords that can be formed using the 21 points \[ = \dfrac{{21 \times 20 \times 19!}}{{2 \times 1 \times 19!}}\]
Therefore, we get
\[ \Rightarrow \]Number of chords that can be formed using the 21 points \[ = 21 \times 10\]
Multiplying 21 by 10, we get
\[ \Rightarrow \] Number of chords that can be formed using the 21 points \[ = 210\]
Therefore, the number of chords that can be formed using the 21 points lying on the circle is 210 chords.
Note:
We used combinations instead of permutations to find the number of chords that can be formed using the points on the circle. A chord is formed using 2 points. Suppose two of the 21 points are A and B. Now, if A is joined to B, the chord is AB. If B is joined to A, the chord is BA. However, BA and AB are the same. If we used permutations, the chords AB and BA will be counted as 2 different chords. Therefore, we have used combinations since it does not matter which point is the initial points and which point is the terminal point.
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