
What is the chemical formula of nickel bisulphate?
Answer
497.1k+ views
Hint: As we know that in chemistry, periodic tables play a vital role. In the periodic table there are totally \[118\] elements. In the periodic table there are totally \[18\] columns and \[7\] rows. The columns are called groups. Hence, \[18\] groups in the periodic table. The rows are called periods. Hence, totally \[7\] period in the table. In chemistry each element has a specific symbol in the periodic table. We first know the symbol of every element in the given molecule. The chemical name depends on the symbol of the element and number of the element count in the molecule. In written chemical names of molecules having some rules and regulation. In chemical formulas, the symbol of a metal atom is written first and others are written next.
Complete answer:
The atomic symbol of nickel is \[Ni\].
The molecular symbol of bisulphate is \[HS{O_4}\].
The chemical formula of nickel bisulphate is \[Ni{(HS{O_4})_2}\]. Nickel is the one of the divalent metals in the modern periodic table. Normally nickel bisulphate is dehydrated from. So, the stable from nickel bisulphate is \[Ni{(HS{O_4})_2}.2{H_2}O\].
According to the above discussion we conclude the chemical formula of nickel bisulphate is \[Ni{(HS{O_4})_2}\].
Note:
We have to remember that the atomic number of the element is nothing but the number of electrons or number of protons. The mass number of the atom is nothing but the sum of the number of protons and number of neutrons. The sum of the total oxidation number of the atom in the molecule is zero. If it is zero it means the molecule is in a stable state. If suppose, the sum of the oxidation number of the atom is greater than zero or positive value. That molecule is considered a cationic compound. In other cases, the sum of the oxidation number of the atom in the molecule is less than zero means that the molecule is considered an ionic compound. The anionic and cationic compounds are less stable than neutral molecules.
Complete answer:
The atomic symbol of nickel is \[Ni\].
The molecular symbol of bisulphate is \[HS{O_4}\].
The chemical formula of nickel bisulphate is \[Ni{(HS{O_4})_2}\]. Nickel is the one of the divalent metals in the modern periodic table. Normally nickel bisulphate is dehydrated from. So, the stable from nickel bisulphate is \[Ni{(HS{O_4})_2}.2{H_2}O\].
According to the above discussion we conclude the chemical formula of nickel bisulphate is \[Ni{(HS{O_4})_2}\].
Note:
We have to remember that the atomic number of the element is nothing but the number of electrons or number of protons. The mass number of the atom is nothing but the sum of the number of protons and number of neutrons. The sum of the total oxidation number of the atom in the molecule is zero. If it is zero it means the molecule is in a stable state. If suppose, the sum of the oxidation number of the atom is greater than zero or positive value. That molecule is considered a cationic compound. In other cases, the sum of the oxidation number of the atom in the molecule is less than zero means that the molecule is considered an ionic compound. The anionic and cationic compounds are less stable than neutral molecules.
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