What is the change in resistance of a wire which is stretched triple its length?
Answer
547.5k+ views
Hint:The opposition to the flow of electrical current into an electrical circuit is known as resistance. As current flows through a cable, it produces resistance, is the resistance of wire.
Complete step by step answer:
It is necessary to keep in mind that a wire's resistance is inversely proportional to its area but directly proportional to its length. We can calculate the change in resistance by applying the formula,
\[R = \dfrac{{\rho L}}{A}\]
Where, \[\rho \] is the resistivity of the wire, $L$ is the length of the wire and $A$ is the cross sectional area of the wire.
That is, Resistance} =(Specific Resistivity Constant $\times$ Length of wire)} / Area of cross section of wire
\[R\alpha L\]
Therefore we can say that when the length of the wire is tripled then resistance will also become three times
\[R\alpha \dfrac{1}{A}\]
That is, the cross-section of the wire is cut to one third of its original cross-section, when it is extended to three times its original length. As a result from the above relationship, we find that the current resistance is 9 times that of the original resistance.
Note:Remember the formula \[R = \dfrac{{\rho L}}{A}\]. It is also important to note that resistance is directly proportional to length and inversely proportional to area. The longer a wire is, the more resistance it has because electrons must travel a longer path to get from one end to the other. The lower the resistance, the greater the cross sectional field, so the electrons have more space to pass through. This holds true regardless of how thick the wire is.
Complete step by step answer:
It is necessary to keep in mind that a wire's resistance is inversely proportional to its area but directly proportional to its length. We can calculate the change in resistance by applying the formula,
\[R = \dfrac{{\rho L}}{A}\]
Where, \[\rho \] is the resistivity of the wire, $L$ is the length of the wire and $A$ is the cross sectional area of the wire.
That is, Resistance} =(Specific Resistivity Constant $\times$ Length of wire)} / Area of cross section of wire
\[R\alpha L\]
Therefore we can say that when the length of the wire is tripled then resistance will also become three times
\[R\alpha \dfrac{1}{A}\]
That is, the cross-section of the wire is cut to one third of its original cross-section, when it is extended to three times its original length. As a result from the above relationship, we find that the current resistance is 9 times that of the original resistance.
Note:Remember the formula \[R = \dfrac{{\rho L}}{A}\]. It is also important to note that resistance is directly proportional to length and inversely proportional to area. The longer a wire is, the more resistance it has because electrons must travel a longer path to get from one end to the other. The lower the resistance, the greater the cross sectional field, so the electrons have more space to pass through. This holds true regardless of how thick the wire is.
Recently Updated Pages
Master Class 12 Business Studies: Engaging Questions & Answers for Success

Master Class 12 Biology: Engaging Questions & Answers for Success

Master Class 12 Chemistry: Engaging Questions & Answers for Success

Class 12 Question and Answer - Your Ultimate Solutions Guide

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Trending doubts
Explain the Treaty of Vienna of 1815 class 10 social science CBSE

Which Indian city is known as the "City of Victory"?

Which instrument is used to measure the Blood Pressure?

Who Won 36 Oscar Awards? Record Holder Revealed

What is the median of the first 10 natural numbers class 10 maths CBSE

Why is it 530 pm in india when it is 1200 afternoon class 10 social science CBSE

