
Chandana counted 32 wheels of some buses and cars. If a bus has 6 wheels and a car has 4 wheels. How many buses and cars were there?
Answer
600.9k+ views
Hint: Here, first take the number of buses as $x$ and the number of cars as $y$. Now, we can express 32 in the form, $32=6x+4y$. Now, consider the possible values of $x$ and $y$ where we will get the sum as 32, which will be the required number of buses and cars.
Complete step-by-step solution -
We are given that Chandana counted 32 wheels of some buses and cars. The number of wheels of buses are 6 and the number of wheels of cars are 4.
Now, we have to find the number of buses and cars.
Total number of wheels counted by Chandana = 32
Number of wheels of buses = 6
Number of wheels of cars = 4
Let $x$ be the number of buses and $y$ be the number of cars.
Now, we can express 32 as the sum of two numbers in such a way that one is divisibe by 6 and the other is divisible by 4.
Hence, 32 can be expressed as:
$32=6x+4y$
Here, 32 can be expressed in two ways.
For $x=2$ and $y=5$, we will get:
$\begin{align}
& 32=6\times 2+4\times 5 \\
& 32=12+20 \\
\end{align}$
Similarly, for $x=4$and $y=2$, we will obtain:
$\begin{align}
& 32=6\times 4+4\times 2 \\
& 32=24+8 \\
\end{align}$
Here, there are two possibilities:
One of the possibilities is that there would be 2 buses and 5 cars.
The other possibility is that there would be 4 buses and 2 cars.
Note: Here, without checking randomly we can also find the solution by considering the HCF of 4 and 6. The HCF is 2, now for $x=2$, find the value of $y$. Similarly, for $y=2$, find the value of $x$.
Complete step-by-step solution -
We are given that Chandana counted 32 wheels of some buses and cars. The number of wheels of buses are 6 and the number of wheels of cars are 4.
Now, we have to find the number of buses and cars.
Total number of wheels counted by Chandana = 32
Number of wheels of buses = 6
Number of wheels of cars = 4
Let $x$ be the number of buses and $y$ be the number of cars.
Now, we can express 32 as the sum of two numbers in such a way that one is divisibe by 6 and the other is divisible by 4.
Hence, 32 can be expressed as:
$32=6x+4y$
Here, 32 can be expressed in two ways.
For $x=2$ and $y=5$, we will get:
$\begin{align}
& 32=6\times 2+4\times 5 \\
& 32=12+20 \\
\end{align}$
Similarly, for $x=4$and $y=2$, we will obtain:
$\begin{align}
& 32=6\times 4+4\times 2 \\
& 32=24+8 \\
\end{align}$
Here, there are two possibilities:
One of the possibilities is that there would be 2 buses and 5 cars.
The other possibility is that there would be 4 buses and 2 cars.
Note: Here, without checking randomly we can also find the solution by considering the HCF of 4 and 6. The HCF is 2, now for $x=2$, find the value of $y$. Similarly, for $y=2$, find the value of $x$.
Recently Updated Pages
Two men on either side of the cliff 90m height observe class 10 maths CBSE

What happens to glucose which enters nephron along class 10 biology CBSE

Cutting of the Chinese melon means A The business and class 10 social science CBSE

Write a dialogue with at least ten utterances between class 10 english CBSE

Show an aquatic food chain using the following organisms class 10 biology CBSE

A circle is inscribed in an equilateral triangle and class 10 maths CBSE

Trending doubts
Why is there a time difference of about 5 hours between class 10 social science CBSE

Write a letter to the principal requesting him to grant class 10 english CBSE

What is the median of the first 10 natural numbers class 10 maths CBSE

The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths

Which of the following does not have a fundamental class 10 physics CBSE

State and prove converse of BPT Basic Proportionality class 10 maths CBSE

