
CaO is basic based on the following reaction:
$ 6CaO + {P_4}{O_{10}}\xrightarrow{{}}2C{a_3}{\left( {P{O_4}} \right)_2} $
If true enter 1, else enter 0.
Answer
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Hint: Salt is a chemical compound that has both cations and anions. In other words they are electrically neutral compounds that contain equal numbers of cations (positively charged ions) and anions (negatively charged ions). The ions that make up the salt can be inorganic, organic, monatomic or polyatomic.
Complete step by step answer
A salt is an electrically neutral chemical compound that is made of equal number of cations and anions of any kind. The formation of these salts happens in a lot of ways.
An acid and a base can come together and react to form a salt compound.
A metal and an acid can react to form a salt compound.
A metal ion and a non-metal ion can react to form a salt compound.
A base and an acid anhydride (acid compound that is water deficient) to form a salt compound.
An acid and a base anhydride (base compound that is water deficient) to form a salt.
Two salts can undergo double displacement reactions in the presence of water to form an insoluble salt precipitate.
A salt can be formed in all these ways. Although a common feature is that a proton donor and a proton acceptor react to form salts.
In the given equation we have $ 6CaO + {P_4}{O_{10}}\xrightarrow{{}}2C{a_3}{\left( {P{O_4}} \right)_2} $ . In which $ {P_4}{O_{10}} $ is an oxide of a non metal that when undergo hydrolysis gives an acid.
$ {P_4}{O_{10}} + 6{H_2}O\xrightarrow{{}}4{H_3}P{O_4} $
Since on hydrolysis we get an acid, $ {P_4}{O_{10}} $ is an acidic oxide. Now the product of the given reaction is a salt with 2 ions, $ C{a^{2 + }} $ and $ PO_4^{3 - } $ . Since there are 3 ions of $ C{a^{2 + }} $ and 2 ions of $ PO_4^{3 - } $ the total charge of $ + 6 $ and $ - 6 $ is balanced to give us a salt, $ C{a_3}{\left( {P{O_4}} \right)_2} $ .
We know that an acid reacts with a base to form a salt. And $ {P_4}{O_{10}} $ is an acidic oxide, so $ CaO $ is a base in this reaction that reacts with an acidic oxide to form a salt $ C{a_3}{\left( {P{O_4}} \right)_2} $ .
Thus, it is true, i.e. 1.
Note
On a simpler note, we know that $ CaO $ is a metal-oxide, and it reacts with water to form a base, so $ Cao $ is a basic oxide.
$ CaO + {H_2}O\xrightarrow{{}}Ca{\left( {OH} \right)_2} $
Complete step by step answer
A salt is an electrically neutral chemical compound that is made of equal number of cations and anions of any kind. The formation of these salts happens in a lot of ways.
An acid and a base can come together and react to form a salt compound.
A metal and an acid can react to form a salt compound.
A metal ion and a non-metal ion can react to form a salt compound.
A base and an acid anhydride (acid compound that is water deficient) to form a salt compound.
An acid and a base anhydride (base compound that is water deficient) to form a salt.
Two salts can undergo double displacement reactions in the presence of water to form an insoluble salt precipitate.
A salt can be formed in all these ways. Although a common feature is that a proton donor and a proton acceptor react to form salts.
In the given equation we have $ 6CaO + {P_4}{O_{10}}\xrightarrow{{}}2C{a_3}{\left( {P{O_4}} \right)_2} $ . In which $ {P_4}{O_{10}} $ is an oxide of a non metal that when undergo hydrolysis gives an acid.
$ {P_4}{O_{10}} + 6{H_2}O\xrightarrow{{}}4{H_3}P{O_4} $
Since on hydrolysis we get an acid, $ {P_4}{O_{10}} $ is an acidic oxide. Now the product of the given reaction is a salt with 2 ions, $ C{a^{2 + }} $ and $ PO_4^{3 - } $ . Since there are 3 ions of $ C{a^{2 + }} $ and 2 ions of $ PO_4^{3 - } $ the total charge of $ + 6 $ and $ - 6 $ is balanced to give us a salt, $ C{a_3}{\left( {P{O_4}} \right)_2} $ .
We know that an acid reacts with a base to form a salt. And $ {P_4}{O_{10}} $ is an acidic oxide, so $ CaO $ is a base in this reaction that reacts with an acidic oxide to form a salt $ C{a_3}{\left( {P{O_4}} \right)_2} $ .
Thus, it is true, i.e. 1.
Note
On a simpler note, we know that $ CaO $ is a metal-oxide, and it reacts with water to form a base, so $ Cao $ is a basic oxide.
$ CaO + {H_2}O\xrightarrow{{}}Ca{\left( {OH} \right)_2} $
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