Question

Calculate the sum of four times the largest negative integer and the smallest positive integer.
$
  A. {\text{ - 3}} \\
  {\text{B. - 2}} \\
  {\text{C. - 1}} \\
  {\text{D. 0}} \\
  {\text{E. 1}} \\
 $

Answer 1

Hint- Here we will proceed by taking the largest negative integer i.e. -1 and the smallest positive integer i.e. 1, we will add both the integers and get the required result.

Complete Step-by-Step solution:
As we know the largest negative integer is -1 and the smallest positive integer is 1.
According to the question-
We are given four times the largest negative integer and the smallest positive integer.
Which implies that 4(-1) + 1
$ \Rightarrow - 4 + 1$
$\Rightarrow -3$
Therefore, the sum of four times the largest negative integer and the smallest positive integer is -3.
Hence option A is correct.

Note- While solving this question, we must know that the largest negative integer is -1 and the smallest positive integer is 1. Also one must be careful while reading the given condition and applying it to get the required answer.