Question

Calculate the specific heat capacity of oil when $5040J$ of heat energy is required to raise the temperature of $60g$ oil by $40K$.
A. \[2500JK{g^{ - 1}}{K^{ - 1}}\]
B. \[2100JK{g^{ - 1}}{K^{ - 1}}\]
C. \[1500JK{g^{ - 1}}{K^{ - 1}}\]
D. \[2700JK{g^{ - 1}}{K^{ - 1}}\]

Answer 1

Hint: Here in the given situation we see that the temperature of the oil is to be raised. So, to raise the temperature of the oil we need heat energy which is already given. So, by using the formula for the heat energy required to raise the temperature, we can find the value of the specific heat capacity. (since the formula includes the value of the specific heat capacity).

Complete answer:
First, we will write the given quantities in the question to get the clear idea.
Given,
Heat energy= $Q = 5040J$
Mass= $m = 0.06g$
Rise in temperature = $\Delta T = 40K$
We know that the specific heat energy of any liquid is given by the formula,
$Q = mC\Delta T$
This formula can be arranged to get the value of the specific heat capacity,
$C = \dfrac{Q}{{m\Delta T}}$-----equation (1)
So, by using this rearranged formula for the specific heat capacity for the given condition, we get
Putting all the values in the equation (1), we get
$C = \dfrac{{5040J}}{{0.06Kg \times 40\Delta T}}$
$ \Rightarrow C = \dfrac{{5040J}}{{2.40Kg\Delta T}}$
$C = 2100JK{g^{ - 1}}{K^{ - 1}}$
So the specific heat capacity of oil when $5040J$ of heat energy is required to raise the temperature of $60g$ oil by $40K$ is $2100JK{g^{ - 1}}{K^{ - 1}}$.

So, the correct answer is “Option B”.

Note:
Here in the above question we have seen the role of the heat energy so we should have a clear idea about what is heat energy? Heat energy is energy which is the result of tiny particles called atoms, molecules or the ions in the solids, liquids, or gases. Transfer of heat energy from one object to another object is possible by the three methods named conduction, convection and radiation.