How do you calculate the slope of \[\left( {{\mathbf{0}},{\mathbf{5}}} \right)\] and \[\left( {{\mathbf{5}},{\mathbf{0}}} \right)?\]
Answer
559.2k+ views
Hint: Slope denotes the steepness and direction of lines. If a line passes through two points $ ({x_1},{y_1}) $ and $ ({x_2},{y_2}) $ , then its slope $ m $ is given by the formula $ m = \dfrac{{\Delta y}}{{\Delta x}} = \dfrac{{{y_2} - {y_1}}}{{{x_2} - {x_1}}} $ .
Complete step-by-step answer:
In this question we have to find the slope of a line with coordinate points $ (0,5) $ and $ (5,0) $ .
We know that the formula to find slope of an equation when two points are given is:
$ m = \dfrac{{\Delta y}}{{\Delta x}} = \dfrac{{{y_2} - {y_1}}}{{{x_2} - {x_1}}} - - - (1) $
In the given question, let $ ({x_1},{y_1}) = (0,5) $ and $ ({x_2},{y_2}) = (5,0) $ .
Here, $ {x_1} = 0 $ , $ {y_1} = 5 $ and $ {x_2} = 5 $ , $ {y_2} = 0 $ .
Using these values let us now find the value of slope $ m $ .
First, let us find the value of $ \Delta y $ .
$
\Delta y = {y_2} - {y_1} = 0 - 5 \\
\Rightarrow \Delta y = - 5 \;
$
Similarly, let us find the value of $ \Delta x $ .
$
\Delta x = {x_2} - {x_1} = 5 - 0 \\
\Rightarrow \Delta x = 5 \;
$
Now, let us substitute these values in the equation of slope, equation $ (1) $ ,
$
m = \dfrac{{ - 5}}{5} \\
\Rightarrow m = - 1 \;
$
Thus, the slope of $ (0,5) $ and $ (5,0) $ is found to be $ - 1 $ .
So, the correct answer is “-1”.
Note: The value of slope changes as the number changes. Hence, while substituting the values for \[{x_1},{y_1},{x_2},{\text{ and }}{{\text{y}}_2}\], we have to make sure right value Is substituted. Or else the value of slope will be altered. A slope can be positive, negative, constant, and undefined.
$ \bullet $ The slope is positive, that is, $ m > 0 $ , when the line goes up from left to right.
$ \bullet $ The slope is negative, that is, $ m < 0 $ , when the line goes down from left to right.
$ \bullet $ The slope is zero or constant, when the line is horizontal.
$ \bullet $ The slope is undefined, when the line is vertical.
Complete step-by-step answer:
In this question we have to find the slope of a line with coordinate points $ (0,5) $ and $ (5,0) $ .
We know that the formula to find slope of an equation when two points are given is:
$ m = \dfrac{{\Delta y}}{{\Delta x}} = \dfrac{{{y_2} - {y_1}}}{{{x_2} - {x_1}}} - - - (1) $
In the given question, let $ ({x_1},{y_1}) = (0,5) $ and $ ({x_2},{y_2}) = (5,0) $ .
Here, $ {x_1} = 0 $ , $ {y_1} = 5 $ and $ {x_2} = 5 $ , $ {y_2} = 0 $ .
Using these values let us now find the value of slope $ m $ .
First, let us find the value of $ \Delta y $ .
$
\Delta y = {y_2} - {y_1} = 0 - 5 \\
\Rightarrow \Delta y = - 5 \;
$
Similarly, let us find the value of $ \Delta x $ .
$
\Delta x = {x_2} - {x_1} = 5 - 0 \\
\Rightarrow \Delta x = 5 \;
$
Now, let us substitute these values in the equation of slope, equation $ (1) $ ,
$
m = \dfrac{{ - 5}}{5} \\
\Rightarrow m = - 1 \;
$
Thus, the slope of $ (0,5) $ and $ (5,0) $ is found to be $ - 1 $ .
So, the correct answer is “-1”.
Note: The value of slope changes as the number changes. Hence, while substituting the values for \[{x_1},{y_1},{x_2},{\text{ and }}{{\text{y}}_2}\], we have to make sure right value Is substituted. Or else the value of slope will be altered. A slope can be positive, negative, constant, and undefined.
$ \bullet $ The slope is positive, that is, $ m > 0 $ , when the line goes up from left to right.
$ \bullet $ The slope is negative, that is, $ m < 0 $ , when the line goes down from left to right.
$ \bullet $ The slope is zero or constant, when the line is horizontal.
$ \bullet $ The slope is undefined, when the line is vertical.
Recently Updated Pages
Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Class 11 Question and Answer - Your Ultimate Solutions Guide

Master Class 11 Biology: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Accountancy: Engaging Questions & Answers for Success

Trending doubts
Differentiate between an exothermic and an endothermic class 11 chemistry CBSE

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

In what year Guru Nanak Dev ji was born A15 April 1469 class 11 social science CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

