Calculate the residue obtained on heating $2.76g$ of $A{g_2}{(CO)_3}$.
$A{g_2}{(CO)_3}\xrightarrow{\Delta }\,2Ag + C{O_2} + \dfrac{1}{2}{O_2}$
Answer
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Hint:This question is based on the mole concept. The mole concept tells us about the amount of substance in different ways. It can be expressed as the mass of a substance that has $6.023 \times {10^{ - 23}}$ number of atoms. This number in chemistry is called Avogadro’s number.
Complete step by step answer:
The chemical name of the compound $A{g_2}{(CO)_3}$ is silver carbonate. It is obtained through the precipitation of silver nitrate with an alkaline carbonate. It is generally white but it gets yellow when you wash the soluble salts present in the compound. It also changes color when you expose it to sunlight. Unlike other metal carbonates, which decomposes into metal oxides liberating $C{O_2}$ gas, silver nitrate on heating yields residue of silver and a mixture of carbon dioxide and oxygen gas. The reaction for which is given above:
$A{g_2}{(CO)_3}\xrightarrow{\Delta }\,2Ag + C{O_2} + \dfrac{1}{2}{O_2}$
The molar mass of $A{g_2}{(CO)_3}$ is $276g$, and the molar mass of $Ag$ is $108g$.
$1$ mole of $A{g_2}{(CO)_3}$ gives $2$mole of $Ag$ i.e.
On heating $276g$ of $A{g_2}{(CO)_3}$ we get $216g$ of residue,
$1g$ of $A{g_2}{(CO)_3}$ gives $\dfrac{{216}}{{276}}g$ residue,
Now, the residue obtained from $2.76g$ of $A{g_2}{(CO)_3}$ will be $\dfrac{{216}}{{276}} \times 2.76 = 2.16g$
Hence, On heating $2.76g$ of $A{g_2}{(CO)_3}$ the amount of residue obtained is $2.16g$
ADDITIONAL INFORMATION:
The conversion of $A{g_2}{(CO)_3}$ into silver residue is an example of decomposition reaction. Decomposition reactions are those reactions in which compounds break into one or more constituent molecules or atoms when they are given some energy as input.
Note:
Silver nitrate is majorly used in the production of silver powder in microelectronics. It is also used as a reagent in the organic synthesis, as an oxidizing agent to form diols from lactones in the Feliz oxidation process. It also functions as a base in Wittig reaction.
Complete step by step answer:
The chemical name of the compound $A{g_2}{(CO)_3}$ is silver carbonate. It is obtained through the precipitation of silver nitrate with an alkaline carbonate. It is generally white but it gets yellow when you wash the soluble salts present in the compound. It also changes color when you expose it to sunlight. Unlike other metal carbonates, which decomposes into metal oxides liberating $C{O_2}$ gas, silver nitrate on heating yields residue of silver and a mixture of carbon dioxide and oxygen gas. The reaction for which is given above:
$A{g_2}{(CO)_3}\xrightarrow{\Delta }\,2Ag + C{O_2} + \dfrac{1}{2}{O_2}$
The molar mass of $A{g_2}{(CO)_3}$ is $276g$, and the molar mass of $Ag$ is $108g$.
$1$ mole of $A{g_2}{(CO)_3}$ gives $2$mole of $Ag$ i.e.
On heating $276g$ of $A{g_2}{(CO)_3}$ we get $216g$ of residue,
$1g$ of $A{g_2}{(CO)_3}$ gives $\dfrac{{216}}{{276}}g$ residue,
Now, the residue obtained from $2.76g$ of $A{g_2}{(CO)_3}$ will be $\dfrac{{216}}{{276}} \times 2.76 = 2.16g$
Hence, On heating $2.76g$ of $A{g_2}{(CO)_3}$ the amount of residue obtained is $2.16g$
ADDITIONAL INFORMATION:
The conversion of $A{g_2}{(CO)_3}$ into silver residue is an example of decomposition reaction. Decomposition reactions are those reactions in which compounds break into one or more constituent molecules or atoms when they are given some energy as input.
Note:
Silver nitrate is majorly used in the production of silver powder in microelectronics. It is also used as a reagent in the organic synthesis, as an oxidizing agent to form diols from lactones in the Feliz oxidation process. It also functions as a base in Wittig reaction.
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