
Calculate the relative molecular mass of the each of the following:
\[
{\text{(i) Ammonium dichromate [(N}}{{\text{H}}_{\text{4}}}{{\text{)}}_{\text{2}}}{\text{C}}{{\text{r}}_{\text{2}}}{{\text{O}}_{\text{7}}}{\text{]}} \\
{\text{(ii)}}\;{\text{Hydrated Copper Sulphate [CuS}}{{\text{O}}_{\text{4}}}{\text{.5}}{{\text{H}}_{\text{2}}}{\text{O]}} \\
{\text{(H = 1,N = 14,O = 16,S = 32,Cr = 52,Cu = 64)}} \\
\]
Answer
558.6k+ views
Hint: A molecular formula is a chemical formula which indicates the type of atoms and the number of atoms present in a molecule of a compound. We can find out the relative molecular mass of a molecule if we have the molecular formula.
Complete step by step answer:
Relative molecular mass is the ratio of the sum of masses of each atom of a compound to the unified mass of the compound. It can be calculated simply by the addition of individual masses of the atoms present in a compound.
(i) First, we are taking the case of \[{\text{Ammonium dichromate [(N}}{{\text{H}}_{\text{4}}}{{\text{)}}_{\text{2}}}{\text{C}}{{\text{r}}_{\text{2}}}{{\text{O}}_{\text{7}}}{\text{]}}\]
We are given the atomic masses of the atoms and we will add it up.
$ {{[2 \times (14 + 4 \times 4)] + 2 \times }}\;{{52 + 7 \times 16}} \\
{{ = [2 \times (14 + 16)] + 104 + 112}} \\
{{ = 60 + 104 + 112}} \\
{{ = 276}}$
The answer is \[{\text{276}}\;{\text{u}}\].
(ii) Next, we are taking the case of \[{\text{Hydrated Copper Sulphate [CuS}}{{\text{O}}_{\text{4}}}{\text{.5}}{{\text{H}}_{\text{2}}}{\text{O]}}\]
As we have done above, we have to add the individual atomic masses like this;
${{64 + 32 + 4 \times 16 + [5 \times (2 \times 1) + 16]}} \\
{{ = 64 + 32 + 64 + 26}} \\
{{ = 186}}\;{\text{u}} $
Therefore, the answer is \[{\text{186}}\;{\text{u}}\].
Additional Information:
Atomic mass is defined on the basis of carbon atoms. One atomic mass unit is defined as the one-twelfth of the mass of a carbon atom. Carbon atom is taken as the base because it is found abundantly and is present even in the fossils as isotopes etc.
Note: Molecular formula gives us the basic information about a molecule or compound. It provides information about the kind of atoms present in it and the number of atoms used in the formation of the molecule. It also helps us to calculate the molecular mass of the compound.
Complete step by step answer:
Relative molecular mass is the ratio of the sum of masses of each atom of a compound to the unified mass of the compound. It can be calculated simply by the addition of individual masses of the atoms present in a compound.
(i) First, we are taking the case of \[{\text{Ammonium dichromate [(N}}{{\text{H}}_{\text{4}}}{{\text{)}}_{\text{2}}}{\text{C}}{{\text{r}}_{\text{2}}}{{\text{O}}_{\text{7}}}{\text{]}}\]
We are given the atomic masses of the atoms and we will add it up.
$ {{[2 \times (14 + 4 \times 4)] + 2 \times }}\;{{52 + 7 \times 16}} \\
{{ = [2 \times (14 + 16)] + 104 + 112}} \\
{{ = 60 + 104 + 112}} \\
{{ = 276}}$
The answer is \[{\text{276}}\;{\text{u}}\].
(ii) Next, we are taking the case of \[{\text{Hydrated Copper Sulphate [CuS}}{{\text{O}}_{\text{4}}}{\text{.5}}{{\text{H}}_{\text{2}}}{\text{O]}}\]
As we have done above, we have to add the individual atomic masses like this;
${{64 + 32 + 4 \times 16 + [5 \times (2 \times 1) + 16]}} \\
{{ = 64 + 32 + 64 + 26}} \\
{{ = 186}}\;{\text{u}} $
Therefore, the answer is \[{\text{186}}\;{\text{u}}\].
Additional Information:
Atomic mass is defined on the basis of carbon atoms. One atomic mass unit is defined as the one-twelfth of the mass of a carbon atom. Carbon atom is taken as the base because it is found abundantly and is present even in the fossils as isotopes etc.
Note: Molecular formula gives us the basic information about a molecule or compound. It provides information about the kind of atoms present in it and the number of atoms used in the formation of the molecule. It also helps us to calculate the molecular mass of the compound.
Recently Updated Pages
Which cell organelles are present in white blood C class 11 biology CBSE

What is the molecular geometry of BrF4 A square planar class 11 chemistry CBSE

How can you explain that CCl4 has no dipole moment class 11 chemistry CBSE

Which will undergo SN2 reaction fastest among the following class 11 chemistry CBSE

The values of mass m for which the 100 kg block does class 11 physics CBSE

Why are voluntary muscles called striated muscles class 11 biology CBSE

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Discuss the various forms of bacteria class 11 biology CBSE

Explain zero factorial class 11 maths CBSE

State the laws of reflection of light

Difference Between Prokaryotic Cells and Eukaryotic Cells

Show that total energy of a freely falling body remains class 11 physics CBSE

