
How do you calculate the percent composition of chromium in \[BaCr{O_4}\]?
Answer
544.5k+ views
Hint: The percent composition is the percentage of the weight of a component in a compound. It expresses the amount responsible or the weight contribution of a component in the total weight of the compound.
Complete step by step answer:
The percentage composition of a component present in a compound is termed as the ratio of the amount of each component and the sum of amounts of all the components present in the compound multiplied by \[100\]. In general for convenience the amounts are measured in grams of the component.
The significance of percent composition is that it helps in determining the empirical and the molecular formula of a compound. The reverse is also true that if the formula of the compound is known then the percent composition of each component is evaluated.
The percentage composition of a component is expressed by the following mathematical equation as,
$P{C_x} = \dfrac{{{w_x}}}{{MW}} \times 100$ where \[P{C_x}\] is the percent composition of the component\[x\], \[{w_x}\] is the amount of the component \[x\] and \[MW\] is the total weight of all the components present in the compound. The factor \[100\] is multiplied to express the fraction amount in terms of percentage.
The following steps are employed for determining the percent composition of \[BaCr{O_4}\].
a. At first the molar mass of the compound \[BaCr{O_4}\] is evaluated by adding up the atomic masses of each of the atoms present in \[BaCr{O_4}\].
Molar mass = atomic mass of \[Ba\]+ atomic mass of \[Cr\]+ \[4{\text{ }} \times \] atomic mass of \[O\]
=$137 + 52 + 4 \times 16 = 253g$
As the compound contains a single chromium atom so the weight of the chromium atom is \[52.0g\]. Hence the percent composition of chromium in \[BaCr{O_4}\] is
$P{C_{Cr}} = \dfrac{{{w_{Cr}}}}{{MW}} \times 100$
$P{C_{Cr}} = \dfrac{{52}}{{253}} \times 100 = 20.5\% $
Note:
The percent composition should not be confused with the mole fraction of a compound. The mole fraction is also a ratio of the moles of a compound in a mixture of compounds or solutions. But a percent composition is an element percent determination which constitutes a fraction in a compound.
Complete step by step answer:
The percentage composition of a component present in a compound is termed as the ratio of the amount of each component and the sum of amounts of all the components present in the compound multiplied by \[100\]. In general for convenience the amounts are measured in grams of the component.
The significance of percent composition is that it helps in determining the empirical and the molecular formula of a compound. The reverse is also true that if the formula of the compound is known then the percent composition of each component is evaluated.
The percentage composition of a component is expressed by the following mathematical equation as,
$P{C_x} = \dfrac{{{w_x}}}{{MW}} \times 100$ where \[P{C_x}\] is the percent composition of the component\[x\], \[{w_x}\] is the amount of the component \[x\] and \[MW\] is the total weight of all the components present in the compound. The factor \[100\] is multiplied to express the fraction amount in terms of percentage.
The following steps are employed for determining the percent composition of \[BaCr{O_4}\].
a. At first the molar mass of the compound \[BaCr{O_4}\] is evaluated by adding up the atomic masses of each of the atoms present in \[BaCr{O_4}\].
Molar mass = atomic mass of \[Ba\]+ atomic mass of \[Cr\]+ \[4{\text{ }} \times \] atomic mass of \[O\]
=$137 + 52 + 4 \times 16 = 253g$
As the compound contains a single chromium atom so the weight of the chromium atom is \[52.0g\]. Hence the percent composition of chromium in \[BaCr{O_4}\] is
$P{C_{Cr}} = \dfrac{{{w_{Cr}}}}{{MW}} \times 100$
$P{C_{Cr}} = \dfrac{{52}}{{253}} \times 100 = 20.5\% $
Note:
The percent composition should not be confused with the mole fraction of a compound. The mole fraction is also a ratio of the moles of a compound in a mixture of compounds or solutions. But a percent composition is an element percent determination which constitutes a fraction in a compound.
Recently Updated Pages
Why are manures considered better than fertilizers class 11 biology CBSE

Find the coordinates of the midpoint of the line segment class 11 maths CBSE

Distinguish between static friction limiting friction class 11 physics CBSE

The Chairman of the constituent Assembly was A Jawaharlal class 11 social science CBSE

The first National Commission on Labour NCL submitted class 11 social science CBSE

Number of all subshell of n + l 7 is A 4 B 5 C 6 D class 11 chemistry CBSE

Trending doubts
Differentiate between an exothermic and an endothermic class 11 chemistry CBSE

10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

State the laws of reflection of light

