
Calculate the monthly bill of if a heater of\[100\] watt is used at the rate of Rs. \[1perunit\] For \[1hour\] daily.
A. \[Rs.200\]
B. \[Rs.6000\]
C. \[Rs.100\]
D. \[Rs.3\]
Answer
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Hint: Through the given data in the question firstly will calculate total energy consumed in one month and then will calculate the cost of total energy consumed that is monthly bill of heater used of \[100watt\].
Complete step by step answer:
As in the given question we are provided with power of heater as, \[P = 100watt\]
\[P = 0.1kW\]
And we are also given with cost of per unit used as, \[{C_{elec.}} = Rs.1\]
One we have also given with time it is used in a day, \[t = 1hour\]
Now to calculate the total energy, \[E = P \times t\], now substitute the values of power and time in given formula
\[E = 0.1 \times 1\]
\[E = 0.1kWh\]
Now to calculate the energy used in total days is
\[{E_{total}} = 30 \times 0.1\]
\[{E_{total}} = 3kWh\]
Now calculate the cost of total energy used in a month
\[C{_{monthly}} = 1 \times 3\]
\[C{_{monthly}} = Rs.3\]
Therefore the answer is option D.
Additional Information: Electric warming is a cycle where electrical vitality is changed over to warm vitality. Regular applications incorporate space warming, cooking, water warming and modern cycles. An electric warmer is an electrical gadget that changes over an electric flow into heat. The warming component inside each electric radiator is an electrical resistor, and takes a shot at the standard of Joule warming: an electric flow going through a resistor will change over that electrical vitality into heat vitality. Most present day electric warming gadgets use nichrome wire as the dynamic component; the warming component, portrayed on the right, utilizes nichrome wire upheld by clay encasings.
Note: Now take care of calculating the total energy converting it to standard units like in this question we have converted it to standard \[kW\]from \[watt\]and if sometime we are given with time in \[\sec \]convert it to \[hour\]. Also it is important to note that the unit in an electricity bill implies kWh hence we have used kWh throughout the problem as the basic energy unit instead of joules
Complete step by step answer:
As in the given question we are provided with power of heater as, \[P = 100watt\]
\[P = 0.1kW\]
And we are also given with cost of per unit used as, \[{C_{elec.}} = Rs.1\]
One we have also given with time it is used in a day, \[t = 1hour\]
Now to calculate the total energy, \[E = P \times t\], now substitute the values of power and time in given formula
\[E = 0.1 \times 1\]
\[E = 0.1kWh\]
Now to calculate the energy used in total days is
\[{E_{total}} = 30 \times 0.1\]
\[{E_{total}} = 3kWh\]
Now calculate the cost of total energy used in a month
\[C{_{monthly}} = 1 \times 3\]
\[C{_{monthly}} = Rs.3\]
Therefore the answer is option D.
Additional Information: Electric warming is a cycle where electrical vitality is changed over to warm vitality. Regular applications incorporate space warming, cooking, water warming and modern cycles. An electric warmer is an electrical gadget that changes over an electric flow into heat. The warming component inside each electric radiator is an electrical resistor, and takes a shot at the standard of Joule warming: an electric flow going through a resistor will change over that electrical vitality into heat vitality. Most present day electric warming gadgets use nichrome wire as the dynamic component; the warming component, portrayed on the right, utilizes nichrome wire upheld by clay encasings.
Note: Now take care of calculating the total energy converting it to standard units like in this question we have converted it to standard \[kW\]from \[watt\]and if sometime we are given with time in \[\sec \]convert it to \[hour\]. Also it is important to note that the unit in an electricity bill implies kWh hence we have used kWh throughout the problem as the basic energy unit instead of joules
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