Question

How do you calculate the mass of a rectangular solid that has a density of \[3.14g/c{m^3}\] and measures \[2.50cm\] by \[1.30{\text{ }}cm\] by \[3.00{\text{ }}cm\] ?

Answer 1

Hint: Density gauges the smallness in atomic plan in any substance which decides how weighty or light any substance is. Mass units are most usually grams or kilograms. Volume units are most normally cubic centimeters ($cm^3$), cubic meters ($m^3$), or milliliters (mL).
The density equation is,
\[Density = \dfrac{{Mass}}{{Volume}}\]

Complete step by step answer:
First calculate the volume of the solid as follows,
$Volume = 2.50cm \times 1.30cm \times 3.00cm$
On simplification we get,
$Volume = 9.75c{m^3}$
It is given that the density of the solid is \[3.14g/c{m^3}\].
Let us calculate the mass of the solid as follows,
$mass = \dfrac{{3.14g/c{m^3}}}{{9.75c{m^3}}} = 0.32g$
The mass of the rectangular solid is $0.32g$.

Note:
Now we can discuss the utilizations of Density:
Referred to all the more conventionally as "smooth movement lights", these gadgets got well known in the \[1970's\] and give a decent, if to some degree hypnotizing delineation of thickness and lightness in real life as the masses of overflowing goes here and there in always evolving shapes. These lights comprise a holder of water where is put a shaded natural slick fluid that doesn't blend in with water, consequently establishing a subsequent stage. The creation of the oil stage is with the end goal that its thickness is somewhat more noteworthy than that of water at room temperature, so it ordinarily lives at the lower part of the compartment. At the point when the light is turned on, a warmth source (as a rule a brilliant light) disguised in the base of the compartment warms the oil stage. This lessens its thickness to an incentive underneath that of the water; making masses of oil ascend to the highest point of the compartment. Being presently far taken out from the warmth source, the masses chill off and sink back to the base, where they rehash the cycle.