Question

Calculate the equivalent weight of $KMn{{O}_{4}}$ in acidic medium.

Answer 1

Hint: We know that different species tend to behave differently in different mediums, so based on the medium \[KMn{{O}_{4}}\] act as an oxidiser in an acidic medium. Equivalent weight is the weight per equivalent that reacts. An equivalent is a reacting packet. It is an amount that will react.

Complete step by step answer:
We know that \[KMn{{O}_{4}}\] is a strong oxidising agent, meaning it will get reduced to oxidise another species.
Equivalent weight of a substance (oxidant or reductant) is equal to the molecular weight divided by the number of electrons lost or gained by one molecule of the substance in redox reaction.
$\begin{align}
  & Equivalent\,weight\,of\,oxidi\sin g\,agent=\frac{Molecular\,weight}{Number\,of\,electrons\,gained\,by\,one\,molecule}= \\
 & \frac{Molecular\,Weight}{Change\,in\,Oxidation\,Number} \\
\end{align}$

$\begin{align}
  & Equivalent\,weight\,of\,\operatorname{Re}ducing\,agent=\frac{Molecular\,weight}{Number\,of\,electrons\,lost\,by\,one\,molecule}= \\
 & \frac{Molecular\,Weight}{Change\,in\,Oxidation\,Number} \\
\end{align}$

In acidic medium
\[Mn{{O}_{4}}^{-}\text{ }+\text{ }8{{H}^{+}}\text{ }+\text{ }5{{e}^{-}}\text{ }=\text{ }M{{n}^{2+}}+4{{H}_{2}}O\]
From this reaction we can deduce that \[M{{n}^{7+}}\] reduced to \[M{{n}^{2+}}\]so number of electrons gained for this reaction is 5
\[Equivalent\,weight\text{ }=\text{ }\frac{molecular\text{ }weight\text{ }}{\text{ }n\text{ }factor}\]
So, for \[KMn{{O}_{4}}\] molecular weight is 158 gram
\[Equivalent\,weight\text{ }=\text{ }\frac{158}{\text{ 5}}=31.6\,per\,equivalent\]
So, our answer is 31.6 per equivalent.
Note: We should always keep a check about n factor, which is decided by the factor from number of electrons gained or lost during reaction in acidic and basic medium. We should revise concepts about determining n factors of various chemical species.
We should know about Potassium permanganate. When we observe potassium permanganate, it appears as a purplish colour crystalline solid. It is non-combustible. We should be careful that it doesn’t come in contact with sulphuric acid, as result in spontaneous ignition.