
Calculate the distance travelled by a man walking at a speed of $5km/h$in $36$minutes.
A. $3km$
B. $4km$
C. $5km$
D. $6km$
Answer
573.6k+ views
Hint: The speed of an object is defined as the distance travelled by the object in unit time.
The distance $d$ travelled by the object moving with speed $s$ in time $t$is given as,
$d = s \times t$.
Complete step by step answer:
You have given in the question speed of the man
$s = 5km/h$.
Time $t = 36$minute.
You have to find the distance $d$travelled by the man.
You first convert the units of time and speed to the same form either speed in $m/s$and time in $s$or speed $km/h$and time in $h$.
Here, speed in $km/h$ so you should convert time in $hour$.
You know, $1\min = \dfrac{1}{{60}}hour$so, $36\min $have,
$t = 36 \times \dfrac{1}{{60}}h$ .
When, speed $s$and time $t$ Then Distance $d$ is,
$d = s \times t$
Put values,
$d = 5km/h \times \dfrac{{36}}{{60}}h$
$d = 3km$.
So, the correct answer is “Option A”.
Additional Information:
1. To convert speed in $km/h$ to $m/s$you have to use below formula,
$1km/h = \dfrac{5}{{18}}m/s$.
You should also know how this formula come,
So, you know $1km$
$1h = 60\min $ and $1\min = 60\sec $,
So, $1h = 60 \times 60\sec $
Know,
$1km/h = \dfrac{{1000m}}{{60 \times 60s}}$
Simplify, $1km/h = \dfrac{5}{{18}}m/s$.
2. From the speed formula you can find any one unknown if you have given two known quantities.
i.e.
If speed $s$and time $t$is given then, you can find third unknown distance $d$ by making use of below formula,
$d = s \times t$
If speed $s$ and distance $d$ is given then, you can find time $t$ required use below formula,
$t = \dfrac{d}{s}$
If distance $d$ and time $t$is given the speed $s$ of the object is given as,
$s = \dfrac{d}{t}$.
Note:
You should always check the units of speed, distance and time. If speed in $km/h$then, time should be in $h$ and distance in $km$. Same for other units.
The distance $d$ travelled by the object moving with speed $s$ in time $t$is given as,
$d = s \times t$.
Complete step by step answer:
You have given in the question speed of the man
$s = 5km/h$.
Time $t = 36$minute.
You have to find the distance $d$travelled by the man.
You first convert the units of time and speed to the same form either speed in $m/s$and time in $s$or speed $km/h$and time in $h$.
Here, speed in $km/h$ so you should convert time in $hour$.
You know, $1\min = \dfrac{1}{{60}}hour$so, $36\min $have,
$t = 36 \times \dfrac{1}{{60}}h$ .
When, speed $s$and time $t$ Then Distance $d$ is,
$d = s \times t$
Put values,
$d = 5km/h \times \dfrac{{36}}{{60}}h$
$d = 3km$.
So, the correct answer is “Option A”.
Additional Information:
1. To convert speed in $km/h$ to $m/s$you have to use below formula,
$1km/h = \dfrac{5}{{18}}m/s$.
You should also know how this formula come,
So, you know $1km$
$1h = 60\min $ and $1\min = 60\sec $,
So, $1h = 60 \times 60\sec $
Know,
$1km/h = \dfrac{{1000m}}{{60 \times 60s}}$
Simplify, $1km/h = \dfrac{5}{{18}}m/s$.
2. From the speed formula you can find any one unknown if you have given two known quantities.
i.e.
If speed $s$and time $t$is given then, you can find third unknown distance $d$ by making use of below formula,
$d = s \times t$
If speed $s$ and distance $d$ is given then, you can find time $t$ required use below formula,
$t = \dfrac{d}{s}$
If distance $d$ and time $t$is given the speed $s$ of the object is given as,
$s = \dfrac{d}{t}$.
Note:
You should always check the units of speed, distance and time. If speed in $km/h$then, time should be in $h$ and distance in $km$. Same for other units.
Recently Updated Pages
Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Class 11 Question and Answer - Your Ultimate Solutions Guide

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Trending doubts
What is meant by exothermic and endothermic reactions class 11 chemistry CBSE

10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

What are Quantum numbers Explain the quantum number class 11 chemistry CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

