
Calculate the $\Delta H$in joules for: C (graphite) $ \to $C (diamond) from the data:
C (graphite) + ${O_2}$(g) $ \to $$C{O_2}$(g); \[\Delta {H^o}\] = -393.5kJ
C (graphite) + ${O_2}$(g) $ \to $$C{O_2}$(g); \[\Delta {H^o}\] = -395.4kJ
A.1.9 kJ
B.$ - 7889 \times {10^3}$
C.190000
D.$ + 7889 \times {10^3}$
Answer
598.8k+ views
Hint: In this question, we have to find the transfer of heat from graphite to Diamond. Use the values given in the question to solve and find the heat energy. Use Hess's law for chemical equations to find your answer.
Complete answer:
According to the given information
C (graphite) + ${O_2}$(g) $ \to $$C{O_2}$(g); \[\Delta {H_1}\] = -393.5kJ (equation 1)
C (graphite) + ${O_2}$(g) $ \to $$C{O_2}$(g); \[\Delta {H_2}\] = -395.4kJ (equation 2)
On reversing equation 2
\[C{O_2} \to C + {O_2};\vartriangle H_2^1 = + 395.4kJ\] (Equation 3)
Adding equation 1 and 3
$C + {O_2} + C{O_2} = C{O_2} + {O_2}$
Now $\Delta H = \Delta {H_1} + \Delta {H_2}$
$\Delta H = - 393.5 + 395.4$
$\Delta H = 1.9kJ$
$\Delta H = 1900Joules$
Thus option A”1.9kJ” is the correct answer to the problem.
Note: According to Hess’ Law, if a chemical equation can be written as the sum of many other chemical equations, the enthalpy change of the first chemical equation is equivalent to the sum of the enthalpy changes of the other chemical equations.
Complete answer:
According to the given information
C (graphite) + ${O_2}$(g) $ \to $$C{O_2}$(g); \[\Delta {H_1}\] = -393.5kJ (equation 1)
C (graphite) + ${O_2}$(g) $ \to $$C{O_2}$(g); \[\Delta {H_2}\] = -395.4kJ (equation 2)
On reversing equation 2
\[C{O_2} \to C + {O_2};\vartriangle H_2^1 = + 395.4kJ\] (Equation 3)
Adding equation 1 and 3
$C + {O_2} + C{O_2} = C{O_2} + {O_2}$
Now $\Delta H = \Delta {H_1} + \Delta {H_2}$
$\Delta H = - 393.5 + 395.4$
$\Delta H = 1.9kJ$
$\Delta H = 1900Joules$
Thus option A”1.9kJ” is the correct answer to the problem.
Note: According to Hess’ Law, if a chemical equation can be written as the sum of many other chemical equations, the enthalpy change of the first chemical equation is equivalent to the sum of the enthalpy changes of the other chemical equations.
Recently Updated Pages
Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Accountancy: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

Discuss the various forms of bacteria class 11 biology CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

