Calculate the coefficient of correlation between $x$ and $y$ for the data
x 1 2 3 4 5 6 7 8 9 10 y 3 10 5 1 2 9 4 8 7 6
A) 0.12
B) 0.19
C) 0.22
D) 0.62
| x | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 |
| y | 3 | 10 | 5 | 1 | 2 | 9 | 4 | 8 | 7 | 6 |
Answer
591k+ views
Hint: To calculate the coefficient to correlation, we will be using Karl Pearson’s coefficient of correlation which is given by ${r_{xy}} = \dfrac{{n\sum {{x_i}{y_i}} - \sum {{x_i}} \sum {{y_i}} }}{{\sqrt {n\sum {{x_i}^2} - {{\left( {\sum {{x_i}} } \right)}^2}} \sqrt {n\sum {{y_i}^2} - {{\left( {\sum {{y_i}} } \right)}^2}} }}$. Since there are ten terms, $n = 10$. A table is drawn to find the required terms to be substituted in Karl Pearson’s coefficient of correlation equation and do further simplification.
Complete step-by-step answer:
We need to find the correlation coefficient between $x$ and $y$.
Karl Pearson’s coefficient of correlation is given as
${r_{xy}} = \dfrac{{n\sum {{x_i}{y_i}} - \sum {{x_i}} \sum {{y_i}} }}{{\sqrt {n\sum {{x_i}^2} - {{\left( {\sum {{x_i}} } \right)}^2}} \sqrt {n\sum {{y_i}^2} - {{\left( {\sum {{y_i}} } \right)}^2}} }}$
Where $n$ is the number of terms.
${x_i}$ is the sum of values of $x$.
${y_i}$ is the sum of values of $y$.
Now, find the values,
Substitute the values in the formula,
$ \Rightarrow {r_{xy}} = \dfrac{{10 \times 321 - 55 \times 55}}{{\sqrt {10 \times 385 - {{\left( {55} \right)}^2}} \sqrt {10 \times 385 - {{\left( {55} \right)}^2}} }}$
Simplify the terms,
$ \Rightarrow {r_{xy}} = \dfrac{{3210 - 3025}}{{\sqrt {3850 - 3025} \times \sqrt {3850 - 3025} }}$
Subtract the values,
$ \Rightarrow {r_{xy}} = \dfrac{{185}}{{\sqrt {825} \times \sqrt {825} }}$
We know that,
$\sqrt a \times \sqrt a = {\left( {\sqrt a } \right)^2} = a$
Use this formula in the denominator,
$ \Rightarrow {r_{xy}} = \dfrac{{185}}{{825}}$
Divide numerator by the denominator,
$\therefore {r_{xy}} = 0.22$
Hence, option (C) is correct.
Note: The degree of correlation can be determined as follows:
There will be a perfect correlation between two variables if the value of the correlation coefficient is near $ \pm 1$, that is, as one variable increases, the other variable tends to also increase (if positive) or decrease (if negative).
There will be a high degree of correlation or strong correlation between two variables if the value of the correlation coefficient lies between $ \pm 0.5$ and $ \pm 1$.
There will be a moderate degree of correlation or medium correlation between two variables if the value of the correlation coefficient lies between $ \pm 0.3$ and $ \pm 0.49$.
There will be a low degree of correlation or a small correlation between two variables if the value of the correlation coefficient lies below $ \pm 0.29$.
There will be no correlation between the two variables if the value of the correlation coefficient is zero.
Complete step-by-step answer:
We need to find the correlation coefficient between $x$ and $y$.
Karl Pearson’s coefficient of correlation is given as
${r_{xy}} = \dfrac{{n\sum {{x_i}{y_i}} - \sum {{x_i}} \sum {{y_i}} }}{{\sqrt {n\sum {{x_i}^2} - {{\left( {\sum {{x_i}} } \right)}^2}} \sqrt {n\sum {{y_i}^2} - {{\left( {\sum {{y_i}} } \right)}^2}} }}$
Where $n$ is the number of terms.
${x_i}$ is the sum of values of $x$.
${y_i}$ is the sum of values of $y$.
Now, find the values,
| $x$ | $y$ | ${x^2}$ | ${y^2}$ | $xy$ |
| 1 | 3 | 1 | 9 | 3 |
| 2 | 10 | 4 | 100 | 20 |
| 3 | 5 | 9 | 25 | 15 |
| 4 | 1 | 16 | 1 | 4 |
| 5 | 2 | 25 | 4 | 10 |
| 6 | 9 | 36 | 81 | 54 |
| 7 | 4 | 49 | 16 | 28 |
| 8 | 8 | 64 | 64 | 64 |
| 9 | 7 | 81 | 49 | 63 |
| 10 | 6 | 100 | 36 | 60 |
| $\sum {{x_i}} = 55$ | $\sum {{y_i}} = 55$ | $\sum {{x_i}^2} = 385$ | $\sum {{y_i}^2} = 385$ | $\sum {{x_i}{y_i}} = 321$ |
Substitute the values in the formula,
$ \Rightarrow {r_{xy}} = \dfrac{{10 \times 321 - 55 \times 55}}{{\sqrt {10 \times 385 - {{\left( {55} \right)}^2}} \sqrt {10 \times 385 - {{\left( {55} \right)}^2}} }}$
Simplify the terms,
$ \Rightarrow {r_{xy}} = \dfrac{{3210 - 3025}}{{\sqrt {3850 - 3025} \times \sqrt {3850 - 3025} }}$
Subtract the values,
$ \Rightarrow {r_{xy}} = \dfrac{{185}}{{\sqrt {825} \times \sqrt {825} }}$
We know that,
$\sqrt a \times \sqrt a = {\left( {\sqrt a } \right)^2} = a$
Use this formula in the denominator,
$ \Rightarrow {r_{xy}} = \dfrac{{185}}{{825}}$
Divide numerator by the denominator,
$\therefore {r_{xy}} = 0.22$
Hence, option (C) is correct.
Note: The degree of correlation can be determined as follows:
There will be a perfect correlation between two variables if the value of the correlation coefficient is near $ \pm 1$, that is, as one variable increases, the other variable tends to also increase (if positive) or decrease (if negative).
There will be a high degree of correlation or strong correlation between two variables if the value of the correlation coefficient lies between $ \pm 0.5$ and $ \pm 1$.
There will be a moderate degree of correlation or medium correlation between two variables if the value of the correlation coefficient lies between $ \pm 0.3$ and $ \pm 0.49$.
There will be a low degree of correlation or a small correlation between two variables if the value of the correlation coefficient lies below $ \pm 0.29$.
There will be no correlation between the two variables if the value of the correlation coefficient is zero.
Recently Updated Pages
Three beakers labelled as A B and C each containing 25 mL of water were taken A small amount of NaOH anhydrous CuSO4 and NaCl were added to the beakers A B and C respectively It was observed that there was an increase in the temperature of the solutions contained in beakers A and B whereas in case of beaker C the temperature of the solution falls Which one of the following statements isarecorrect i In beakers A and B exothermic process has occurred ii In beakers A and B endothermic process has occurred iii In beaker C exothermic process has occurred iv In beaker C endothermic process has occurred

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

State and prove Bernoullis theorem class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

Which among the following are examples of coming together class 11 social science CBSE

