
Calculate the amount and compound interest on ₹15,000 in 3 years when the rate of interest for successive years is 6%, 8% and 10% respectively.
A) ₹3,879.20
B) ₹3,889.20
C) ₹3,789.20
D) ₹3,689.20
Answer
585.9k+ views
Hint: Since three different rate of interests are given for the three years respectively, so we will use the formula for Amount as:
\[A = P\left( {1 + \dfrac{{{r_1}}}{{100}}} \right)\left( {1 + \dfrac{{{r_2}}}{{100}}} \right)\left( {1 + \dfrac{{{r_3}}}{{100}}} \right)\]
And Interest will be the difference between Amount and Principal.
Complete step-by-step solution:
Now, according to the statement of the question, the Principal given is 17000, time is of 3years and the rate of interest for three years is 10% for first year, 10% for second year and 14% for third year.
So now according to the formula, the Amount is given as:
\[A = P\left( {1 + \dfrac{{{r_1}}}{{100}}} \right)\left( {1 + \dfrac{{{r_2}}}{{100}}} \right)\left( {1 + \dfrac{{{r_3}}}{{100}}} \right)\]
And the Interest will be calculated as: Interest = Amount – Principal
Now, first we will calculate the Amount as per the information in the question, using the formula given above:
So,
$
P = Rs.15000 \\
{r_1} = 6\% ,{r_2} = 8\% ,{r_3} = 10\% \\
t = 3years \\
$
Then the amount will be:
$
A = 15000\left( {1 + \dfrac{6}{{100}}} \right)\left( {1 + \dfrac{8}{{100}}} \right)\left( {1 + \dfrac{{10}}{{100}}} \right) \\
= 15000\left( {\dfrac{{100 + 6}}{{100}}} \right)\left( {\dfrac{{100 + 8}}{{100}}} \right)\left( {\dfrac{{100 + 10}}{{100}}} \right) \\
= 15000\left( {\dfrac{{106}}{{100}}} \right)\left( {\dfrac{{108}}{{100}}} \right)\left( {\dfrac{{110}}{{100}}} \right) \\
= \dfrac{{15 \times 106 \times 108 \times 11}}{{100}} \\
= 18889.20 \\
$
Therefore, the Amount is ₹18889.20
$
Interest = Amount - Principal \\
= 18889.20 - 15000 \\
= 3889.20 \\
$
So, after 3 years the total amount earned is ₹18889.20 while the total interest earned is ₹3889.20
Therefore, the total interest earned in 3 years is ₹3889.20
Hence, the correct answer is option B.
Note: To calculate the interest earned we need to calculate the amount first. If there are n different rate of interests for n years, then, the formula for Amount will become:
\[A = P\left( {1 + \dfrac{{{r_1}}}{{100}}} \right)\left( {1 + \dfrac{{{r_2}}}{{100}}} \right)\left( {1 + \dfrac{{{r_3}}}{{100}}} \right).........\left( {1 + \dfrac{{{r_n}}}{{100}}} \right)\]
However, the Interest will always be calculated as the difference of Amount and Principal.. This is accumulated interest , compounded over n years. Hence called Compound Interest with variable rate of interests.
\[A = P\left( {1 + \dfrac{{{r_1}}}{{100}}} \right)\left( {1 + \dfrac{{{r_2}}}{{100}}} \right)\left( {1 + \dfrac{{{r_3}}}{{100}}} \right)\]
And Interest will be the difference between Amount and Principal.
Complete step-by-step solution:
Now, according to the statement of the question, the Principal given is 17000, time is of 3years and the rate of interest for three years is 10% for first year, 10% for second year and 14% for third year.
So now according to the formula, the Amount is given as:
\[A = P\left( {1 + \dfrac{{{r_1}}}{{100}}} \right)\left( {1 + \dfrac{{{r_2}}}{{100}}} \right)\left( {1 + \dfrac{{{r_3}}}{{100}}} \right)\]
And the Interest will be calculated as: Interest = Amount – Principal
Now, first we will calculate the Amount as per the information in the question, using the formula given above:
So,
$
P = Rs.15000 \\
{r_1} = 6\% ,{r_2} = 8\% ,{r_3} = 10\% \\
t = 3years \\
$
Then the amount will be:
$
A = 15000\left( {1 + \dfrac{6}{{100}}} \right)\left( {1 + \dfrac{8}{{100}}} \right)\left( {1 + \dfrac{{10}}{{100}}} \right) \\
= 15000\left( {\dfrac{{100 + 6}}{{100}}} \right)\left( {\dfrac{{100 + 8}}{{100}}} \right)\left( {\dfrac{{100 + 10}}{{100}}} \right) \\
= 15000\left( {\dfrac{{106}}{{100}}} \right)\left( {\dfrac{{108}}{{100}}} \right)\left( {\dfrac{{110}}{{100}}} \right) \\
= \dfrac{{15 \times 106 \times 108 \times 11}}{{100}} \\
= 18889.20 \\
$
Therefore, the Amount is ₹18889.20
$
Interest = Amount - Principal \\
= 18889.20 - 15000 \\
= 3889.20 \\
$
So, after 3 years the total amount earned is ₹18889.20 while the total interest earned is ₹3889.20
Therefore, the total interest earned in 3 years is ₹3889.20
Hence, the correct answer is option B.
Note: To calculate the interest earned we need to calculate the amount first. If there are n different rate of interests for n years, then, the formula for Amount will become:
\[A = P\left( {1 + \dfrac{{{r_1}}}{{100}}} \right)\left( {1 + \dfrac{{{r_2}}}{{100}}} \right)\left( {1 + \dfrac{{{r_3}}}{{100}}} \right).........\left( {1 + \dfrac{{{r_n}}}{{100}}} \right)\]
However, the Interest will always be calculated as the difference of Amount and Principal.. This is accumulated interest , compounded over n years. Hence called Compound Interest with variable rate of interests.
Recently Updated Pages
Master Class 4 Science: Engaging Questions & Answers for Success

Master Class 4 English: Engaging Questions & Answers for Success

Master Class 4 Maths: Engaging Questions & Answers for Success

Class 4 Question and Answer - Your Ultimate Solutions Guide

The number of solutions in x in 02pi for which sqrt class 12 maths CBSE

Write any two methods of preparation of phenol Give class 12 chemistry CBSE

Trending doubts
What is BLO What is the full form of BLO class 8 social science CBSE

Give me the opposite gender of Duck class 8 english CBSE

Full form of STD, ISD and PCO

Citizens of India can vote at the age of A 18 years class 8 social science CBSE

Application to your principal for the character ce class 8 english CBSE

What is the difference between rai and mustard see class 8 biology CBSE

