Question

How do you calculate standard temperature and pressure?

Answer 1

Hint: Standard temperature and pressure are standard sets of conditions for experimental measurements to be established to permit comparisons to be made between different sets of knowledge. The standard temperature and pressure \[\left( {STP} \right)\] are defined as \[{{\text{0}}^ \circ }C\] and \[1atm\] of pressure.

Complete step by step solution:
Standard temperature and pressure describe the environment of a reaction. The quality temperature is adequate to\[273.15{\text{ }}K{\text{ }} = 0^\circ C = 32^\circ F\] . The quality pressure equals to\[1{\text{ }}atm = 760{\text{ }}Torr = 760{\text{ }}torr{\text{ }} = {\text{ }}101.35kPa.\]
The ideal gas equation is written as follows:
\[PV = nRT\]
The above equation is a superb tool for understanding the connection between the quantity , pressure, temperature and amount of a perfect gas during a defined environment which will be controlled for a continuing volume.
By rearranging the above equation, we will find pressure using the subsequent equation:
\[P{\text{ }} = {\text{ }}\dfrac{{nRT}}{V}\]
\[STP\] in chemistry is the abbreviation for normal Temperature and Pressure. \[STP\] most ordinarily is employed when performing calculations on gases, like gas density. The quality temperature is \[273{\text{ }}K{\text{ }}\left( {0^\circ Celsius{\text{ }}or{\text{ }}32^\circ {\text{ }}Fahrenheit} \right)\] and therefore the standard atmosphere is \[1{\text{ }}atm\] pressure.
Today you're getting to prove experimentally that the quantity of \[1mole\] of a gas at degree Centigrade & pressure \[\left( {STP} \right)\] occupies a volume of \[{\text{22}} \cdot 4{\text{ }}liters\] or \[22,400{\text{ }}milliliters\] . The numerical values that are used for \[STP\] are one atmosphere \[\left( {1{\text{ }}atm} \right)\] and \[0\] degrees Celsius \[\left( {0^\circ C} \right){\text{ }}or{\text{ }}273{\text{ }}Kelvin{\text{ }}\left( {273K} \right)\]

Note:
Degree Centigrade and Pressure. Degree Centigrade is adequate to \[0^\circ C\] , which is \[273.15{\text{ }}K\] . Standard atmosphere is \[1atm\] , \[101.3kPa{\text{ }}or{\text{ }}760{\text{ }}mmHg{\text{ }}or{\text{ }}torr\] . \[STP\] is the "standard" condition often used for measuring gas density and volume.